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Flauer [41]
3 years ago
13

The column has a mass of 600 lb/ft and a force of 50 kips applied at the top. The diagonal brace has a 10 kip axial force that c

an be either tension or compression (note that in seismic and wind loading on buildings, braces experience both tension and compression). Assume all elements are pin-connected at their ends, including the two supports.

Physics
1 answer:
drek231 [11]3 years ago
4 0

Answer: the maximum compression force = 59.47 kip

the minimum compression force = 43.33 kip

Explanation:

In this we required to do force balance in order to get maximum and minimum compression force in the column.

the picture below explains the steps to solve the question with diagrams to ease understanding.

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What is the relationship between the mass of an object and the amount of force required to drag it across the table?
hammer [34]

Answer:

Force = mass × acceleration

Explanation:

The amount of force required to drag the object across the table is the product of the mass of the object and acceleration

6 0
3 years ago
Help pleasseeee URGENT
Zina [86]

Answer:

The speed of the 8-ball is 2.125 m/s after the collision.

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:

P=mv

If we have a system of masses, then the total momentum is the sum of all the individual momentums:

P=m_1v_1+m_2v_2+...+m_nv_n

When a collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses, the law of conservation of linear momentum is simplified to:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.

After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.

The above equation is solved for v1':

\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}

\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}

\displaystyle v'_1=\frac{0.34}{0.16}

v'_1=2.125\ m/s

The speed of the 8-ball is 2.125 m/s after the collision.

8 0
3 years ago
Which changes will decrease the electric force between two positively charged objects? Check all that apply.
zaharov [31]

Answer:

Moving them farther apart

Explanation:

The electric field between the two charges Q and q separated by a distance r is given by

E = \frac{K\times Q\times q}{r^{2}}

It shows that the electric field is inversely proportional to the square of the distance between two charges.

So, as the distance between two charges increases, the electric filed between the two charges decreases.

8 0
3 years ago
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The lowest possible temperature in outer space is 3.13 K. What is the rms speed of hydrogen molecules at this temperature? (The
Umnica [9.8K]

Answer:

v_{rms} =196.59 m/s

Given:

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molar mass of molecular hydrogen, m = 2.02 g/mol = 2.02\times 10^{-3}kg/mol

Solution:

To calculate the root mean squarer or rms speed of hydrogen molecule, we use the given formula:

v_{rms} = \sqrt{\frac{3TR}{m}}

where

R = rydberg's constant = 8.314 J/mol-K

Putting the values in the above formula:

v_{rms} = \sqrt{\frac{3\times 3.13\times 8.314}{2.02\times 10^{-3}}}

v_{rms} =196.59 m/s

5 0
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3.1 Two waves A and B have frequencies 256 Hz and 1024 Hz respectively have amplitude in ratio 3:1 1.What is their ratio of freq
scoundrel [369]

Answer:

1. the one with the raito

2. the one that stubbed their toe

Explanation:

8 0
3 years ago
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