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Yanka [14]
2 years ago
15

The conductor is initially electrically neutral, and then a charge q is placed at the center of the hollow space. Suppose the co

nductor initially has a net charge of 7q instead of being neutral. What is the total charge on the interior and on the exterior surface when the q charge is placed at the center
Physics
1 answer:
Anvisha [2.4K]2 years ago
7 0

The total charge on the interior of the conductor is zero.

The total charge on the exterior of the conductor is 8q.

<h3>Total charge on the interior</h3>

Due to large number of electrons available for conduction in a conductor, most of the electrons moves to surface leaving zero net charge inside the conductor.

Thus, the total charge on the interior of the conductor is zero.

<h3>Total charge on the exterior</h3>

The total charge on the exterior of the conductor is calculated as follows;

Q = q + 7q = 8q

Thus, the total charge on the exterior of the conductor is 8q.

Learn more about net charge on interior and exterior of conductors here: brainly.com/question/14653264

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A car mass of 1.2 x 10 kilograms starts from rest and attains a speed of 20 meters/seconds in 5 seconds. What net force acted on
lorasvet [3.4K]

Net force on the car=F=4.8 x 10³ N

Explanation:

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Why is the contribution of the wavelets lying on the back of secondary wave front zero?​
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3 0
2 years ago
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damaskus [11]

Answer:

The answer to the question is;

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B   >→   A   >→    E   >→    C    >→     F    >→     D.

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Therefore the acceleration for each of the satellite is given by

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Satellite C)      \frac{80^2}{2500}   =  2.56 m/s²

Satellite D)      \frac{40^2}{10000}  =  0.16 m/s²

Satellite E)       \frac{120^2}{5000}   =  2.88 m/s²

Satellite F)       \frac{80^2}{10000}  = 0.64 m/s²

Therefore in order of decreasing acceleration, from largest to smallest we have

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No matter what direction you throw it, or with what speed, its acceleration is immediately 9.8 m/s^2 downward as soon as you release it from your hand, and it doesn't change until the ball hits something.

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Answer:

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              m = M(3a/2)/(g + a/2)

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