Jan ran 4 miles north in 28 minutes. What was Jan's average velocity?
1 answer:
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Answer:
(I). The time at highest point 4.0 sec.
(II). It returns to back to its original height in 8.1 sec
Explanation:
Given that,
Velocity
(I). We need to calculate the time at highest point
Using equation of motion
Where, v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
Put the value into the formula
(II). We know that, when the ball to travel from the initial point and reached at initial point then the displacement is zero.
We need to calculate the total time when it returns to back to its original height
Using equation of motion
Where, s = displacement
g = acceleration due to gravity
t = time
u = velocity
Put the value in the equation
Hence. (I). The time at highest point 4.0 sec.
(II). It returns to back to its original height in 8.1 sec