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tankabanditka [31]
3 years ago
8

Jan ran 4 miles north in 28 minutes. What was Jan's average velocity?

Physics
1 answer:
fenix001 [56]3 years ago
6 0

Answer:

3.83 m/s

Explanation:

Given that,

Distance covered by Jan, d = 4 miles

1 mile = 1609.34 m

4 miles = 6437.38 m

Time, t = 28 minutes = 1680 s

Jan's average speed,

v = d/t

v=\dfrac{6437.38\ \text{m}}{1680\ \text{s}}\\\\v=3.83\ \text{m/s}

Hence, the average velocity of Jan is 3.83 m/s.

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Answer:F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]

Explanation:

Given

Three charges of magnitude q is placed at three corners and fourth charge is placed at last corner with -q charge

Force due to the charge placed at diagonally opposite end on -q charge

F_1=\frac{kq(-q)}{(L\sqrt{2})^2}

where  L\sqrt{2}=Distance between the two charges

F_1=-\frac{kq^2}{2L^2}

negative sign indicates that it is an attraction force

Now remaining two charges will apply the same amount of force as they are equally spaced from -q charge

F_2=\frac{kq(-q)}{(L)^2}

The magnitude of force by both the  charge is same but at an angle of 90^{\circ}

thus combination of two forces at 2 and 3 will be

F'=\sqrt{2}\frac{kq^2}{2L^2}

Now it will add with force due to 1 charge

Thus net force will be

F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]

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3 years ago
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Answer:

A

Explanation:

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Each color that we see corresponds to a different _____ of light.
olga55 [171]

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Fill in the term that completes the statement. The north and south poles of a magnetic field produced by an electromagnet will s
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Answer:

when the direction of the Current changes.

Explanation:

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This is a problem where you only need to know the formula and subtitute the numbers to calculate.

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