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nekit [7.7K]
3 years ago
10

Name the two components that make orbital motion, and explain why objects stay in orbit.

Physics
1 answer:
kap26 [50]3 years ago
4 0
For orbits to happen in space there need to be two forces: gravity and forward velocity. The gravity keeps the object from flying into space, while the velocity keeps the object from crashing into the planet.
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A child's first bicycle has 12-inch tires. These tires have a 6-inch radius. How fa r does the bicycle move forward each time th
Lilit [14]

Answer:

a. s = 0.96 m

b. s = 2.15 m

Explanation:

a.

The relationship between the linear displacement and the angular displacement is given as follows:

s = r\theta

where,

s = linear distance covered = ?

r = radius of wheel = (6 in)(0.0254 m/1 in) = 0.1524 m

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad

Therefore,

s = (0.1524\ m) 2\pi

<u>s = 0.96 m</u>

<u></u>

b.

Assuming, we have to find linear displacement here, as well:

s = r\theta

where,

s = linear distance covered = ?

r = radius of wheel = (13.5 in)(0.0254 m/1 in) = 0.3429 m

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad

Therefore,

s = (0.3429 \ m) 2\pi

<u>s = 2.15 m</u>

3 0
3 years ago
The strength of the electric field 0.5 m from a 6 uC charge is
Triss [41]

Answer:

E= 2.158× 10*5N/C

Explanation:

K= 8.99×10*9, q= 6×10*-6C, d= 0.5m

E= kq/d*2

E= (8.99×10*9× 6×10*-6)/0.5*2

E= 215760

E= 2.158 ×10*5N/C

5 0
3 years ago
Please help I’ll give brainliest
marta [7]

Answer:

Repel

Unlike

Atrract

Fur

Balloon

Positivley charged

negative

postive

neutral

Explanation:

It goes from top to bottom

7 0
3 years ago
How many Newtons of force does it take to move a 53 kilogram object?
Sidana [21]
519.75N

explanation: good luck on whatever assignment
3 0
3 years ago
A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t
WINSTONCH [101]

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s

So, the required time is 2.2 seconds.

3 0
2 years ago
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