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3 years ago

Name the two components that make orbital motion, and explain why objects stay in orbit.

1 answer:

4 0

For orbits to happen in space there need to be two forces: gravity and forward velocity. The gravity keeps the object from flying into space, while the velocity keeps the object from crashing into the planet.

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When condensation rates decrease, causing fewer clouds to form, how might humans change their behavior?

Lubov Fominskaja [6]

<span>Humans might hold a picnic outside because of a lack of precipitation.</span>

5 0

2 years ago

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Mary travelled 70 miles/hour due north. This is an example of what?

kolezko [41]

I believe this would be an example of Mary's velocity. We have her speed and direction which is all you need to find velocity.

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2 years ago

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An electron has a kinetic energy of 10.1 eV. The electron is incident upon a rectangular barrier of height 18.2 eV and width 1.0

podryga [215]

Answer:

factor that the electron's probability of tunneling through the barrier increase 2.02029

Explanation:

given data

kinetic energy = 10.1 eV

height = 18.2 eV

width = 1.00 nm

wavelength = 546 nm

solution

we know that probability of tunneling is express as

probability of tunneling = $e^{-2CL}$ .................1

here C is = $\frac{\sqrt{2m(U-E}}{h}$

here h is Planck's constant

c = $\frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-10.1) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}$

c = 2319130863.06

and proton have hf = $\frac{hc}{\lambda } = {1240}{546}$ = 2.27 ev

so electron K.E = 10.1 + 2.27

KE = 12.37 eV

so decay coefficient inside barrier is

c' = $\frac{\sqrt{2m(U-E}}{h}$

c' = $\frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-12.37) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}$

c' = 1967510340

the factor of incerease in transmisson probability is

probability = $e^{2L(c-c')}$

probability = $e^{2\times 1\times 10^{-9} \times (351620523.06)}$

factor probability = 2.02029

3 0

3 years ago

A rod of length 20 cm has two beads attached to its ends. The rod with beads starts rotating from rest. If the beads are to have

exis [7]

Answer:

$\alpha=28.57\frac{rad}{s^2}$

Explanation:

We use the following rotational kinematic equation to calculate the angular acceleration of the rod:

$\omega_f=\omega_0+\alpha t$

Here $\omega_f$ is the final angular speed, $\omega_0\\$ is the initial angular speed and $\alpha$ is the angular acceleration. The rod starts rotating from rest ( $\omega_0=0$ ):