I’m not entirely sure tbh
Answer:
Same magnitude of the 10 nc charge cause the electric field is external.
Explanation:
To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.
As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.
F = qE
If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.
Answer:
Explanation:
An adiabatic process refers to one where there is no exchange of heat.
The equation of state of an adiabatic process is given by,
where,
= pressure
= volume
= constant
Therefore, work done by the gas during expansion is,
(using )
Answer:
10×2=20
10×2÷64=??
I am not sure what you are trying to say...
