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Gre4nikov [31]
2 years ago
7

As a rocket rises, its kinetic energy changes. At the time the rocket reaches its highest point, most of the kinetic energy of r

ocket has been
A permanently destroyed.
B stored in bonds between its atoms.
C changed to thermal energy due to friction.
D transformed into gravitational potential energy.
Physics
2 answers:
Ulleksa [173]2 years ago
7 0
<span>D transformed into gravitational potential energy.</span>
postnew [5]2 years ago
6 0

Answer:

D transformed into gravitational potential energy.

Explanation:

Kinetic energy is the energy associated with movement and potential energy is the energy associated with position in a system. Energy, in general, is the ability to do a job.

Both kinetic and potential energy represent the two fundamental types of existing energy. Any other energy is a different version of kinetic or potential energy or a combination of both. For example, mechanical energy is the combination of kinetic and potential energy.

Kinetic energy is the type of energy that is associated with movement. Anything that is moving has kinetic energy. It can be calculated using the formula:

E_k=\frac{1}{2} mv^2

Where:

m=mass\hspace{3}of\hspace{3}the\hspace{3}object\\v=velocity\hspace{3}of\hspace{3}the\hspace{3}object

Potential energy is the type of energy that is associated with the relative position within a system, that is, the position of an object with respect to another.  It can be calculated using the formula:

E_p=mgh

Where:

g=gravitational\hspace{3}acceleration\hspace{3}constant\\m=mass\hspace{3}of\hspace{3}the\hspace{3}object\\h=It\hspace{3}is\hspace{3}the\hspace{3}distance\hspace{3}(height\hspace{3}in \hspace{3}meters) between\hspace{3}the\hspace{3}Earth\hspace{3}and\hspace{3}the\hspace{3}object.

So, at the highest point, the velocity of the rocket would be zero, and the distance respect to the launch point would be maximum. Hence according to the previous equation its kinetic energy would zero and its potential energy would be the highest. in another words the kinetic energy of rocket has been transformed into gravitational potential energy.

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Which of the following is true?
fenix001 [56]

Answer:

Its either A. Or C cause ive had a question like this before So Im sure But if not Then Im so sorry

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3 years ago
Two tuning forks of frequency 480 hz and 484 hz are struck simultaneously. what is the beat frequency resulting from the two sou
umka21 [38]
Ans: Beat frequency = f_b = 4Hz

Explanation: 
The beat frequency is equal to the absolute value of the difference in frequency of the two waves. In other words, the number of beats per second is equal to the difference in frequency. It is due to the destructive and constructive interference. <span>According to this interference, sound will be soft or loud.

Hence. the formula is:
</span>Beat frequency = f_b = |f_2 - f_1|
<span>
Since,
</span>f_1 = 480Hz
f_2 = 484Hz

Therefore,
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=> Beat frequency = f_b = 4Hz
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3 years ago
True or False:
mart [117]
This is a true statement
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2 years ago
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A uniform string of length 0.50 m is fixed at both ends. Find the
kozerog [31]

Answer:

configuration of string:

Node - Antinode - Node    or N-A-N

This is 1/2 wavelength since a full wavelength is N-A-N-A-N

f (fundamental) = V / wavelength

F0 = 300 m/s / 1 m = 100 / sec

F1 = 300 m/s / .5 m = 600 / sec

Each increase is a multiple of the fundamental since the wavelength

increases by 1/2 wavelength to keep nodes at both ends of the string

4 0
2 years ago
Air enters a turbine operating at steady state at 8 bar, 1600 K and expands to 0.8 bar. The turbine is well insulated, and kinet
kobusy [5.1K]

Answer:

the maximum theoretical work that could be developed by the turbine is 775.140kJ/kg

Explanation:

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

Temperature at inlet of turbine

Temperature at exit of turbine

Pressure at exit of turbine

Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = mm(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m(i) = mass at inlet

m(o)= Mass at outlet

h(i)= Enthalpy at inlet

h(o)= Enthalpy at outlet

W = Work done

Q = Heat transferred

v(i) = Velocity at inlet

v(o)= Velocity at outlet

Z(i)= Height at inlet

Z(o)= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + WW = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}\\

\frac{T_2}{1600K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}\\ = 828.716K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

W = h_i -h_0W = C_p (T_1-T_2)W = 1.005(1600 - 828.716)W = 775.140kJ/Kg

the maximum theoretical work that could be developed by the turbine is 775.140kJ/kg

4 0
2 years ago
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