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1 year ago

The total amount of revenue collected from $1 per unit tariff on this product will be?

Physics

1 answer:

Rzqust [24]1 year ago

6 0

The total amount of revenue collected from $1 per unit tariff on this product will be $7.

What is revenue from tariffs?

A tax rate known as a revenue tariff is one that is used to obtain direct income from company revenues. The level of prices is significantly impacted by a revenue tariff.

How do tariffs bring in money?

As imports reach the domestic market, the government will earn more money because a tariff is a tax. Since import prices are artificially inflated, domestic sectors also profit from less competition.

Learn more about the Tarrif with the help of the given link:

brainly.com/question/11612474

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I understand that the question you are looking for is "The total amount of revenue collected from a $1-per-unit tariff on this product will be: $22. $14. $8. $7".

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The internuclear distance between two closest Ar atoms in solid argon is about 3.8 A. The polarizability of argon is 1.66e-30 m3

oee [108]

Answer:

83.72 K

Explanation:

$\alpha$ = Polarizability of argon = $1.66\times 10^{-30}\ m^3$

I = First ionization = 1521 kJ/mol

r = Distance between atoms = 3.8 A

R = Gas constant = 8.314 J/mol K

T = Boiling point

Potential energy due to dispersion of gas is given by

$P=-\frac{3}{4}\frac{\alpha^2I}{r^6}\\\Rightarrow P=-\frac{3}{4}\frac{(1.66\times 10^{-30})^2\times 1521\times 10^3}{(3.8\times 10^{-10})^6}\\\Rightarrow P=-1044.01\ J/mol$

Kinetic energy is given by

$K=\frac{3}{2}RT$

The potential and kinetic energy will balance each other

$P=\frac{3}{2}RT\\\Rightarrow 1.04401\times 10^{-33}=\frac{3}{2}RT\\\Rightarrow T=\frac{1044.01\times 2}{3\times 8.314}\\\Rightarrow T=83.72\ K$

The boiling point of argon is 83.72 K

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3 years ago

A water pipe having a 4.00 cm inside diameter carries water into the basement of a house at a speed of 1.00 m/s and a pressure o

posledela

Answer:

$8.16\ \text{m/s}$

Explanation:

$d_1$ = Initial diameter = 4 cm

$v_1$ = Initial velocity = 1 m/s

$d_2$ = Final diameter = 7.8 m

$v_2$ = Final velocity

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From the continuity equation we get

$A_1v_1=A_2v_2\\\Rightarrow \pi\dfrac{d_1^2}{4}v_1=\pi\dfrac{d_2^2}{4}v_2\\\Rightarrow v_2=\dfrac{d_1^2}{d_2^2}v_1\\\Rightarrow v_2=\dfrac{4^2}{1.4^2}\times 1\\\Rightarrow v_2=8.16\ \text{m/s}$

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Answer:

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