Answer:
The clock face is divided into sixty equal parts, each minute. The minute hand is located on the 20 minute mark at 6:20, the hour hand located between the 30 minute mark and the 35 minute mark. When the minute hand goes all sixty minutes, the hour hand only moves five, so to figure out the location of the hour hand, we look at how much the hour has progressed, in this case 20 minutes, or one third of the hour. So the minute hand has moved one third of the way through the hour, so has the hour hand moved one third of the way through the five minutes, or, five thirds of a minute, which is one and two thirds minute, one minute forty seconds. That puts the hour hand at thirty minutes plus one minute and forty seconds—at 31min 40sec—which is 11min 40sec farther than the minute hand.
Step-by-step explanation:
Log₄20-log₄ 45+log₄144=
log₄(20/45)+log₄144= (log_a b- log_a c=log_a (b/c) )
log₄[(20*144)/45]= (log_a b +log_a c=log_a (b*c) )
log₄(2880/45)=
log₄(64)=n ⇔ 4^n=64 (log_a x=n ⇔ a^n=x)
4^n=4³ ⇒n=3 (64=4*4*4=4³)
Answer: log₄20-log₄ 45+log₄144=3
Answer:
(2, -1)
Step-by-step explanation:
because that's where the lines intersect
It depends on which number has the greatest absolute value.
Think about it as money
If you owe me $10, this is shown as -10
Now if I give you back 2 dollars (+2), How much money do I still owe you.
The equation is -10+2
I still owe you 8 dollars which is portrayed as -8
Hope this helps :)
For 64 it’s A. , C. , D. and for 3 it’s D. and F
