The area of Tinyville if the population of Tinyville is 405 Tinys while the population density of the Tinyville is 16.2 is 25 Acres.
<h3>What is Ratio?</h3>
A ratio shows us the number of times a number contains another number.
As it is given that the population density of Tinyville is 16.2 Tinys per acre, while the population of Tinyville is 405 Tinys. Therefore, the area of the Tinyville is the ratio of the population of Tinyville to the population density of the Tinyville.
Hence, the area of Tinyville if the population of Tinyville is 405 Tinys while the population density of the Tinyville is 16.2 is 25 Acres.
Learn more about Ratio:
brainly.com/question/1504221
Since is addition you do the opposite and subtract 12 from 12 and -5 then 12 cancels out and -5-12=-17
Answer:
f
(
x
)
=
3
x
3
−
5
x
2
−
47
x
−
15
Explanation:
If the zero is c, the factor is (x-c).
So for zeros of
−
3
,
−
1
3
,
5
, the factors are
(
x
+
3
)
(
x
+
1
3
)
(
x
−
5
)
Let's take a look at the factor
(
x
+
1
3
)
. Using the factor in this form will not result in integer coefficients because
1
3
is not an integer.
Move the
3
in front of the x and leave the
1
in place:
(
3
x
+
1
)
.
When set equal to zero and solved, both
(
x
+
1
3
)
=
0
and
(
3
x
+
1
)
=
0
result in
x
=
−
1
3
.
f
(
x
)
=
(
x
+
3
)
(
3
x
+
1
)
(
x
−
5
)
Multiply the first two factors.
f
(
x
)
=
(
3
x
2
+
10
x
+
3
)
(
x
−
5
)
Multiply/distribute again.
f
(
x
)
=
3
x
3
+
10
x
2
+
3
x
−
15
x
2
−
50
x
−
15
Combine like terms.
f
(
x
)
=
3
x
3
−
5
x
2
−
47
x
−
15
That means you first calculate divide and multiply and at the and plus and minus.
So
12 / 2 + 4 - 2 x 3 =
6 + 4 - 6 = 4
