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3 years ago

What is the answer to this 6/5 = 2/5n and show me how you solved this answer

1 answer:

5 0

$\frac{6}{5} = \frac{2}{5}n\\\sf Multiply~5~on~both~sides\\\\5\times \frac{6}{5}= \frac{2}{5}n\times 5\\Simplify\\\\6 = 2n\\Divide~2~on~both~sides\\\\6 \div 2 = 2n \div 2\\Simplify\\\\ n = 3$

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If a triangle being has an area of 10 square feet what is the length and width of the cover

bekas [8.4K]

Question needs elaboration.

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3 years ago

Given g(x)=-x-3, solve for x when g (x) =6

LiRa [457]

Answer:

x = - 9

Step-by-step explanation:

Given g(x) = - x - 3 and g(x) = 6, then equate, that is

- x - 3 = 6 ( add 3 to both sides )

- x = 9 ( multiply both sides by - 1 )

x = - 9

4 0

3 years ago

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Heyyyyyyyyyyyyyyyyyyyyyyyyyy

mote1985 [20]

Answer:

hiiiiii girlyyy

Step-by-step explanation:

i think the answer is

a/b like a divided by b is the answer

cuz 8 ÷ 3 = 2.7

and 24 ÷ 9 = 2.7

and 40 ÷ 15 = 2.7

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7 0

3 years ago

Read 2 more answers

A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0

3 years ago

p varies directly as q and inversely as r. One set of values is p = 5, q = 1, and r = 2. Find p when q = 10 and r = 50.

Alexeev081 [22]

P = kq/r

5 = k*1/2
k = 2*5 = 10

p = 5*10/50 = 1
P is 1.

Hope it helps!

7 0

3 years ago