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3 years ago

A disturbance sends ripples across water in a tub. These ripples are an example of a rarefaction

1 answer:

3 0

The appropriate response is a Surface wave. It is a seismic wave that goes over the surface of the Earth rather than through it. Surface waves as a rule have bigger amplitudes and longer wavelengths than body waves, and they travel more gradually than body waves do. Adore waves and Rayleigh waves are sorts of surface waves.

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Legacy issues $570,000 of 8.5%, four-year bonds dated January 1, 2019, that pay interest semiannually on June 30 and December 31

choli [55]

Answer:

1) Determine the total bond interest expense to be recognized.

Total bond interest expense over life of bonds:

Amount repaid:

8 payments of $24,225: $193,800

Par value at maturity: $570,000

Total repaid: $763800 (193,800 + 570,000)

Less amount borrowed: $508050

Total bond interest expense: $255750 (763800 - 508,050)

2)Prepare a straight-line amortization table for the bonds' first two years.

Semiannual Interest Period End; Unamortized Discount; Carrying Value

01/01/2019 61,950 508,050

06/30/2019 54,206 515,794

12/31/2019 46,462 523,538

06/30/2020 38,718 531,282

12/31/2020 30,974 539,026

3) Record the interest payment and amortization on June 30:

June 30 Bond interest expense, dr 31969

Discount on bonds payable, Cr (61950/8) 7743.75

Cash, Cr ( 570000*8.5%/2) 24225

4) Record the interest payment and amortization on December 31:

Dec 31 Bond interest expense, Dr 31969

Discount on bonds payable, Cr 7744

Cash, Cr 24225

6 0

3 years ago

Question 8

Marrrta [24]

Answer:

It has a mass of 40 kg.

Explanation:

Because Force = mass x Acceleration or F = m a, we could say that the mass is force/acceleration which in your case is 2,400/60 which equals 40 kg.

3 0

1 year ago

A point charge +2Q is at the origin and a point charge −Q is located along the x axis at x = d as in the figure below. Find a sy

Akimi4 [234]

Answer: A symbolic expression for the net force on a third point charge +Q located along the y axis

$F_N=k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}$

Explanation:

Let the force on +Q charge y-axis due to +2Q charge be $F_1$ and force on +Q charge y axis due to -Q charge on x-axis be $F_2$ .

Distance between the +2Q charge and +Q charge = d units

Distance between the -Q charge and +Q charge = $\sqrt{2}d$ units

$k_e$ = Coulomb constant

$F_1=k_e\frac{(+2Q)(+Q)}{d^2}=k_e\frac{+2Q^2}{d^2} N$

$F_2=k_e\frac{(-Q)(+Q)}{(\sqrt{2}d)^2}=k_e\frac{-Q^2}{2d^2} N$

Net force on +Q charge on y-axis is:

$F_x=F_2sin 45^o=k_e\frac{-Q^2}{2d^2}\times \frac{1}{\sqrt{2}} N$

$F_y=F_1-F_2cos45^o$

$F_y=(F_1-F_2cos45^o)=(k_e\frac{+2Q^2}{d^2})-(k_e\frac{-Q^2}{2d^2}\frac{1}{\sqrt{2}})$

$F_N=\sqrt{F_x^2+F_y^2}$

$|F_N|=|k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}|$

The net froce on the +Q charge on y-axis is

$F_N=k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}$

4 0

3 years ago

Read 2 more answers

The mass of the block in the drawing is 10 kg. The coefficient of static friction between the block and the vertical wall is 0.5

antiseptic1488 [7]

Answer:

The minimum force to start the block moving up the wall = 49 N

Explanation:

Friction: This is the force that tend to oppose the motion of two bodies in contact. The S.I unit of frictional force is Newton (N)

The minimum force required to start the block moving up the wall = Frictional Force.

I.e F = Frictional force.

And, F = μR..........................Equation 1

Where μ = coefficient of static friction, R = Normal reaction.

But R = mg ( on a level surface).................. Equation 2

Where m = mass, g = acceleration due to gravity.

Given: m = 10 kg,

Constant: g = 9.8 m/s²

substituting these values into Equation 2

R = 10 × 9.8

R = 98 N.

Also given: μ = 0.50

Substituting these values into equation 1

F = 98 × 0.5

F = 49 N.

Therefore The minimum force to start the block moving up the wall = 49 N

3 0

3 years ago

a cube of silver has a mass of 21 kg. calculate the length of the cube's side in inches. the density of silver is 10.49 g/cm3.

Marta_Voda [28]

Density- It is a measurement of that how material is packed together tightly.

Its formula is ρ=m/v

where ρ is the density of material

m is the mass

v is the volume

here we have to find the length of cube's side

a cube of silver has a mass = 21 kg. = 21×10³ [∵1kg = 1000g ]

density of silver = 10.49g/cm³

the length of the cube's side = ?

v=m/ρ

l³ = 21×10³ /10.49 ≈ 2×10³ cm³

l =∛(2×10³)cm³

l = 1.26 ×10 = 12.6 cm

l = 4.96 inches [∵ 1 cm = 0.394 inch ]

the length of the cube's side is 4.96 inches

to know more about density :

brainly.com/question/10847047

#SPJ4

3 0

1 year ago