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Vladimir [108]
2 years ago
5

Which option correctly matches the chemical formula of a compound with its name?

Physics
1 answer:
spin [16.1K]2 years ago
7 0

Answer: N2O3, dinitrogen trioxide

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Conduction is usually faster/slower in liquids and certain solids than in gases.
KIM [24]
Conduction is slower in liquids and gases.

Liquids it is convection which transmits more heat.. quicker...

Materials which are good conductors of thermal energy are called thermal conductors.

metals are good thermal conductors.


6 0
3 years ago
Outside our solar system the closest star to earth is Proxima century life from the start takes 2200000 minutes to reach earth.
s2008m [1.1K]

Answer:

2200000 = 2.2E6 min for light from Proxima to reach earth

8.3 min from light sun to reach earth

2.2E6/8.3 = 2.56E5   times for light from Proxima

Proxima is about 256,000 times farther away than the sun

Since the sun is about 93,000,000 = 9.3E7 miles from earth

Proxima is then 9.3E7 * 2.56E5 = 2.4E13 miles away

Note - the speed of light is

3.00E8 m/s * 60 s/min / 1000 m/km = 1.8E7 km/min as given

5 0
2 years ago
What is 3,278,000 as scientific notation?
jonny [76]
3.278*10^6 I think. Sorry if it’s wrong.
4 0
3 years ago
El movimiento de los cuerpos y la formación de imágenes son ejemplos de esta clase de fenómeno ​
77julia77 [94]

Answer:

depende de que fenómenos nos referimos de acuerdo al los cuerpos de formación puede aver movimiento contante

7 0
3 years ago
An electron is accelerated within a particle accelerator using a 100 MV electric potential. The 100 MeV electron moves along an
Delicious77 [7]

Answer:

The length of the tube is 3.92 m.

Explanation:

Given that,

Electric potential = 100 MV

Length = 4 m

Energy = 100 MeV

We need to calculate the value of \gamma

Using formula of relativistic energy

E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

Put the value into the formula

1.6\times10^{-15}= 9.1\times`10^{-31}\times9\times10^{16}(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)=\dfrac{1.6\times10^{-15}}{9.1\times10^{-31}\times9\times10^{16}}

Here, \gamma-1=(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

\gamma-1=0.01953

\gamma=0.01953+1

\gamma=1.01953

We need to calculate the length

Using formula of length

L'=\dfrac{L}{\gamma}

Put the value into the formula

L'=\dfrac{4}{1.01953}

L'=3.92\ m

Hence, The length of the tube is 3.92 m.

8 0
3 years ago
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