Let the one type of the bread be bread A
The second type of the bread be bread B
Let the flour be 'f' and the butter be 'b'
We need 150f + 50b for bread A and 75f + 75b for bread B
We can compare the amount of flour and bread needed for each bread and write them as ratio
FLOUR
Bread A : Bread B
150 : 75
2 : 1
We have a total of 2250gr of flour, and this amount is to be divided into the ratio of 2 parts : 1 part. There is a total of 3 parts.
2250 ÷ 3 = 750 gr for one part then multiply back into the ratio to get
Bread A : Bread B = (2×750) : (1×750) = 1500 : 750
BUTTER
Bread A : Bread B = 50 : 75 = 2 : 3
The amount of butter available, 1250 gr is to be divided into 2 parts : 3 parts.
There are 5 parts in total
1250 ÷ 5 = 250 gr for one part, then multiply this back into the ratio
Bread A: Bread B = (2×250) : (3×250) = 500 : 750
Hence, for bread A we need 1500 gr of flour and 500 gr of butter, and for bread B, we need 750 gr of flour and 750 gr of butter.
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
Answer:
Part A: The total is 57.58
Part B: 19.19 each
Step-by-step explanation:
Part A: 15(3) +3.50(3)=55.50
55.50 plus the 3.75% tip (not really addition i dont know how to find a percentage so i looked that part up) but it come out to $57.58
Part B: 57.58 divided by 3 is $19.19 ( I do 3 because Maria and 2 more friends)
Hope it helps and that it is 100% correct dont come at me if something is wrong with my math
Answer:
Step-by-step explanation:
The equation is undefined for singularity points at 0, 3, then c ≠ 0, c ≠ 3
<h3>What is the graph of the parent function (y)?</h3>
The set of all coordinates (x, y) in the plane that satisfy the equation y = f(x) is the graph of the function. Suppose a function is only specified for a small set of input values, the graph of the function will only have a small number of points, in which each point's x-coordinate represents an input number and its y-coordinate represents an output number.
From the given information,
- The domain for the
is at x ≥ 0, - The range is the set of values that the dependent variable for which the function is defined. f(x) ≥ 0.
In the second question:
Multiply by LCM
Solve c - (c - 3) = 3: True for all c
c ≠ 0, c ≠ 3
Therefore, we can conclude that since the equation is undefined for singularity points at 0, 3, then c ≠ 0, c ≠ 3
Learn more about the graph of a function here:
brainly.com/question/3939432
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