Answer:
3r^3/y^7.
Step-by-step explanation:
9y^-5 / 3y^2r^-3
9 / 3 = 3
y ^-5 / y^2 = y^-7 = 1 / 7y
1 / r^-3 = r^3
So the answer is 3r^3/y^7.
X, 14, 2x - 16 is greater than or equal to 12, 12, add 16 to both sides, divide both sides by 2, x is greater than or equal to 14. each box filled in is represented by the commas in between each phrase. I don’t know the rest but I did get the first part.
You can definitly use a calculator for this
The answer would be
<span>89.2307692308
<span><span><span><span><span>What you do is find out how many times 0.65 can go into 58 to get your answer:)
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To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.
So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to
Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to
So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.