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mina [271]
3 years ago
11

I need help with this problem I didn't really pay that much attention to this part of the subject.​

Mathematics
1 answer:
Flauer [41]3 years ago
4 0

To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.

So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to

\log(3\cdot 3)=\log(9)

Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to

(4-3)\log(9)=\log(9)

So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.

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Need Help
masya89 [10]
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6 0
3 years ago
Please answer my question
lakkis [162]

Replace m with each number in the given set and solve for d(m)


m = 0

d(m) = 7-2(0) = 7-0 = 7

m=1

d(m) =7-2(1) = 7-2 = 5

m = 2

d(m) = 7-2(2) = 7-4 = 3

m=3

d(m) = 7-2(3) = 7-6 = 1


The answers in order from smallest to largest are 1, 3, 5,7

The correct answer would be F.

4 0
3 years ago
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Dima020 [189]
2ab6/3 is the awnser for this one
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3 years ago
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