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mina [271]
3 years ago
11

I need help with this problem I didn't really pay that much attention to this part of the subject.​

Mathematics
1 answer:
Flauer [41]3 years ago
4 0

To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.

So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to

\log(3\cdot 3)=\log(9)

Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to

(4-3)\log(9)=\log(9)

So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.

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caroline and sarah win some money and share it in the ratio of 6:1 caroline gets £70 more than her how much did they get altoget
svetlana [45]
Answer: £84

Explanation:
84-70=14
14*6=84
6:1
84:14
4 0
3 years ago
Let t = 4 and u = 6 + 2i. Find t – u
hjlf

Step-by-step explanation:

t = 4

u = 6 + 2

Find t - u

solu

t - u

= 4 - ( 6 + 2 ) = 4 - 8

Answer is -4

5 0
2 years ago
PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER
laila [671]
The answer is B.
The numbers are doubling but it's also a constant positive and negative
8 0
3 years ago
Four times the square of a certain number increased by 6 times the number equals 108.find the number
slamgirl [31]
To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:

<span>Four times the square of a certain number increased by 6 times the number equals 108.

4x^2 + 6x = 108

The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
5 0
3 years ago
Read 2 more answers
Richard bought a car for $2,500. The value of the car depreciates by 5% each year,
sladkih [1.3K]

Step-by-step explanation:

<em>Hello</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em>

<em>The</em><em> </em><em>answer is option</em><em> </em><em>D</em><em>.</em>

<em>I</em><em> </em><em>have</em><em> </em><em>given</em><em> </em><em>solution</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>picture</em><em>.</em>

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

6 0
3 years ago
Read 2 more answers
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