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zavuch27 [327]
3 years ago
9

Which is not an example of work being done?

Physics
2 answers:
mezya [45]3 years ago
7 0
C. Carrying a backpack to class
ser-zykov [4K]3 years ago
6 0

Answer:

C

Explanation:

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The winch takes in cable at the constant rate of 130 mm/s. if the cylinder mass is 115 kg, determine the tension in cable 1. neg
nikitadnepr [17]
By applying Newton's second law of motion;

ma = mg - T

Where,
m = mass; a = downward accelerations (+ve value) or upward acceleration (-ve value); g = gravitational acceleration; T = tension.

For the current case, the velocity is constant therefore,
a = 0

Then,
0 = mg - T
T = mg = 115*9.81 = 1128.15 N

Tension in the cable is 1128.15 N.
8 0
4 years ago
The ends of a magnet where thee forces are the strongest are called magnets
ladessa [460]
They are called magnets poles.
7 0
4 years ago
when you squeeze the rubber bulb of a perfume atomizer how do you change the air pressure at the top of the tube
LuckyWell [14K]
You push air and perfume out of the tube, creating a small vaccum that pulls more perfume into the tube
8 0
4 years ago
Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use
Sladkaya [172]

Answer:

The speed of the banana just before it hits the water is:

√(2 · g · h) = v

Explanation:

Hi there!

Before Emily throws the banana, its potential energy is:

PE = m · g · h

Where:

PE = potential energy.

m = mass of the banana.

g = acceleration of the banana due to gravity.

h = height of the bridge (distance from the bridge to the ground).

When the banana reaches the water, all its potential energy will have converted to kinetic energy. The equation for kinetic energy is as follows:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass of the banana.

v = speed.

Then, when the banana hits the water:

m · g · h = 1/2 · m · v²

multiply by 2 and divide by m both sides of the equation:

2 · g · h = v²

√(2 · g · h) = v

5 0
3 years ago
Calculate the impulse of a 1kg box that starts from rest and accelerates to 50m/s over a period of 10 seconds.
Tomtit [17]

Answer:

please find attached pdf

Explanation:

Download pdf
5 0
3 years ago
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