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Jobisdone [24]
3 years ago
10

An object slides along a curved track of negligible friction, as shown in the figure. The potential energy U of the object as a

function of the position x is shown in the graph. The object starts at rest at x=0. Which of the following is a correct claim about the motion of the object?
(Would prefer an explanation, but it's not necessary)
A) The kinetic energy of the object is approximately the same at x=2m and x=5m.

B) At x=2m, the object has more potential energy than kinetic energy.

C) The object comes to rest when x=5.5m.

D) The rate of change of the potential energy is a minimum at x=0m.

E) The object achieves its maximum speed at approximately x=3m.

Physics
1 answer:
balandron [24]3 years ago
5 0

Answer:

E) The object achieves its maximum speed at approximately x=3m.

Explanation:

Since the object is moving in gravitational field

potential energy + kinetic energy = constant = 14 J

At  x = 3 m , potential energy is minimum that is zero

kinetic energy will be maximum .

Kinetic energy = 14 - 0 = 14 J

Hence option ( E ) is the answer.

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Neon has 10 electrons; two in the inner level and 8 in its outermost level. Will neon form bonds with other atoms?​
Lana71 [14]

Answer:

no

Explanation:

this is because its valency shell is full so it wont want any other electrons in its valence shell.

6 0
3 years ago
monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central
hjlf

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

<h3>How to find Wavelength of the light?</h3>

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

To learn more about Wavelength of the light refer to:

brainly.com/question/15413360

#SPJ4

5 0
1 year ago
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J. What is the mass of the soccer ball
Savatey [412]
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J.The mass of the soccer ball is 0.4 kgs. This answer is derived from the formula K=1/2 MV^2.So velocity and kinetic energy are given from that mass of the ball is calculated.By substituting the values 500=1/2*M*50*50 which gives M=0.4 Kgs.<span>
</span>
4 0
3 years ago
Read 2 more answers
Kiran drove from City A to City B, a distance of 228 mi. She increased her speed by 12 mi/h for the 400-mi trip from City B to C
Degger [83]

Answer:

From city A to city B her speed was 38 mi/h

Explanation:

The traveled distance can be calculated using this equation:

From city A to city B

228 mi = v · t₁

Where:

v = velocity

t₁ = time it took Kiran to travel the 228 mi from city A to city B

From city B to city C

400 mi = (v + 12 mi/h) · t₂

We also know that the entire trip took 14 h, then:

t₁ + t₂ = 14 h

So, we have a system of three equations with three unknwons:

228 mi = v · t₁

400 mi = (v + 12 mi/h) · t₂

t₁ + t₂ = 14 h

Let´s solve the third equation for t₁:

t₁ = 14 h - t₂

Now let´s replace t₁ in the first equation and solve it for t₂

228 mi = v · t₁

228 mi = v · (14 h - t₂)

228 mi/v - 14 h =  - t₂

t₂ = 14 h - 228 mi/v

Now let´s replace t₂ in the second equation:

400 mi = (v + 12 mi/h) · t₂

400 mi = (v + 12 mi/h) · (14 h - 228 mi/v)

400 mi = 14 h · v - 228 mi + 168 mi - 2736 mi²/(v · h)

400 mi = 14 h · v - 60 mi - 2736 mi²/(v · h)

460 mi = 14 h · v - 2736 mi²/(v · h)

Multiplicate by v both sides of the equation:

460 mi · v = 14 h · v² - 2736 mi²/h

0 = 14 h · v² - 460 mi · v - 2737 mi²/h

Solving the quadratic equation:

v = 38 mi/h

(The other solution of the equation is negative, and therefore discarded)

From city A to city B her speed was 38 mi/h

4 0
3 years ago
A lever with an output arm of 0.8 meter has a mechanical advantage of 6. What is the length of the input
Novosadov [1.4K]
From the law of the lever: 

<span>mechanical advantage= input arm : output arm

input arm- a
output arm-b
</span>mechanical\ advantage= 6\\\\&#10;6=\frac{a}{0,8}\ \ |*0,8\\\\&#10;6*0,8=a\\\\&#10;a=4,8m&#10;&#10;
<span>Input arm is equal 4,8m</span>
4 0
4 years ago
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