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Y_Kistochka [10]
3 years ago
8

Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f

(x)=x4−2x3+x2−32x−240
Mathematics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Find the Length of AC. Round answers to the nearest hundredth (2 decimal places)
lara31 [8.8K]

Answer:

32.78

Step-by-step explanation:

Assuming that we have two right triangles joined together, with one having adjacent side a, with a side of 12 ft opposite reference angle 30°, and the other one having adjacent side b, with a side of 12 ft opposite reference angle 45°. Thus, a + b = length of AC.

Let's find a and b.

Finding a:

Reference angle = 30°

Opp = 12 ft

Adj = a

Using trigonometric ratio formula, we have:

tan(30) = 12/a

Multiply both sides by a

a*tan(30) = 12

Divide both sides by tan(30)

a = 12/tan(30)

a = 20.78 (nearest hundredth)

Finding b:

Reference angle = 45°

Opp = 12 ft

Adj = b

Using trigonometric ratio formula, we have:

tan(45) = 12/b

Multiply both sides by a

b*tan(45) = 12

Divide both sides by tan(45)

b = 12/tan(45)

a = 12

Length of AC = 20.78 + 12 = 32.78

5 0
3 years ago
£60 is divided between Peter, Angad & Nick so that Peter gets twice as much as Angad, and Angad gets three times as much as
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60£

Peter = 2 Angard

Angard = 3 Nick

Peter = 2 Angard = 6 Nick

Angard = 3 Nick

Nick = 1 Nick

6+3+1=10 Nick

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Peter = 6 Nick = 6£*(6) = 36£

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3 0
3 years ago
What is 2 to the power of 4/3 equal to
Reika [66]

Answer:

<h2><u>E</u><u>k</u>sponent</h2>

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\sf{ {2}^{ \frac{4}{3} } }

=  \sqrt[3]{ {2}^{4} }

=   \sqrt[3]{2 \times 2 \times 2 \times 2}

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4 0
1 year ago
How do I solve this
IgorLugansk [536]

Answer:

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Step-by-step explanation:


7 0
3 years ago
One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

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And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0
3 years ago
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