Answer:
32.78
Step-by-step explanation:
Assuming that we have two right triangles joined together, with one having adjacent side a, with a side of 12 ft opposite reference angle 30°, and the other one having adjacent side b, with a side of 12 ft opposite reference angle 45°. Thus, a + b = length of AC.
Let's find a and b.
Finding a:
Reference angle = 30°
Opp = 12 ft
Adj = a
Using trigonometric ratio formula, we have:
tan(30) = 12/a
Multiply both sides by a
a*tan(30) = 12
Divide both sides by tan(30)
a = 12/tan(30)
a = 20.78 (nearest hundredth)
Finding b:
Reference angle = 45°
Opp = 12 ft
Adj = b
Using trigonometric ratio formula, we have:
tan(45) = 12/b
Multiply both sides by a
b*tan(45) = 12
Divide both sides by tan(45)
b = 12/tan(45)
a = 12
Length of AC = 20.78 + 12 = 32.78
60£
Peter = 2 Angard
Angard = 3 Nick
Peter = 2 Angard = 6 Nick
Angard = 3 Nick
Nick = 1 Nick
6+3+1=10 Nick
60£/10 = 6£
Nick = 6£
Angvard = 3 Nick = 6£*(3) = 18£
Peter = 6 Nick = 6£*(6) = 36£
(prove: 6+18+36=60£)
Answer:
<h2><u>E</u><u>k</u>sponent</h2>
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Answer:
divide
Step-by-step explanation:
One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:

And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees

Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel