Which part of an atom would be found orbiting the nucleus?

The circulatory system transports oxygen and nutrients to cells of the body. What does it remove from the body?

Vitek1552 [10]

B, carbon dioxide and other wastes

5 0

4 years ago

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Describe the kinds of potential energy that are stored by a car driving on a hill.

Ilia_Sergeevich [38]

Answer:

The internal combustion engine in the car converts the potential chemical energy in gasoline and oxygen into thermal energy which is transformed into the mechanical energy that accelerates the vehicle (increasing its kinetic energy) by causing the pressure and performing the work on the pistons.

Explanation:

7 0

3 years ago

Write a scientific explanation that answers the following question: How do you know scientifically that fat and soap are differe

Fantom [35]

Fat and soap are different substances. One reason is that they have a different malleability. The Soap is very hard and sturdy. The fat is soft. Also, soap and fat are different because they had different smells. The soap had a refreshing smell and a soapy one and the fat smelled rubbery like Play-doh. Another reason why fat and soap are different substances is that they don’t dissolve the same in water and oil. Soap is soluble in water and shortening is not soluble in water. Soap is not soluble in oil and shortening is soluble in oil. In the water shortening did not become cloudy but soap did. When placed in oil, the shortening disappeared completely, while soap did not change at all.The melting point of the fat was 57.6 we could not find the melting point of the soap. The soaps melting point is higher than the water's boiling point. A property is something that describes an object and does not change. For example, the soap is white, where the fat is off white. Color is a property. Fat and soap are also different because they have different densities. The soap sank but the fat floated. The density of fat is about .88 g/ml and the density of soap is about 1.18 g/ml. Fat and soap are not the same substances one reason is they have different properties.Malleability, hardness, solubility, melting point,color, and density are all properties. A property is a characteristic of a substance that does not change. Different substances have different properties. If they had the same properties, they would be the same substance, but, since they don’t, they are different substances.

Hope this helps :D

5 0

4 years ago

I

GrogVix [38]

Abhishek Singh present invention to provide

8 0

3 years ago

compound consists of carbon, hydrogen and fluorine. In one experiment, combustion of 2.50 g of the compound produced 3.926 g of

arlik [135]

Answer: The empirical and molecular formula of the compound is $CH_2F$ and $C_{14}H_{28}F_{14}$ respectively

Explanation:

We are given:

Mass of $CO_2=3.926g$

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.926 g of carbon dioxide, $\frac{12}{44}\times 3.926=1.071g$ of carbon will be contained.

To calculate the percentage composition of element in sample, we use the equation:

$\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100$ ......(1)

For Carbon:

Mass of carbon = 1.071 g

Mass of sample = 2.50 g

Putting values in equation 1, we get:

$\%\text{ composition of carbon}=\frac{1.071g}{2.50g}\times 100=42.84\%$

For Fluorine:

Mass of fluorine = 2.54 g

Mass of sample = 5.00 g

Putting values in equation 1, we get:

$\%\text{ composition of fluorine}=\frac{2.54g}{5.00g}\times 100=50.8\%$

Percent composition of hydrogen = [100 - 42.84 - 50.8] % = 6.36 %

We are given:

Percentage of C = 42.84 %

Percentage of F = 50.8 %

Percentage of H = 6.36 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 42.84 g

Mass of F = 50.8 g

Mass of H = 6.36 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.84g}{12g/mole}=3.57moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{6.36g}{1g/mole}=6.36moles$

Moles of Fluorine = $\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{50.8g}{19g/mole}=2.67moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.67 moles.

For Carbon = $\frac{0.072}{2.67}=1.34\approx 1$

For Hydrogen = $\frac{6.36}{2.67}=2.38\approx 2$

For Fluorine = $\frac{2.67}{2.67}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : F = 1 : 2 : 1

The empirical formula for the given compound is $CH_2F$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 448.4 g/mol

Mass of empirical formula = $12+(2\times 1)+19]=33g/mol$

Putting values in above equation, we get:

$n=\frac{448.4g/mol}{33g/mol}=13.6\approx 14$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(14\times 1)}H_{(14\times 2)}F_{(14\times 1)}=C_{14}H_{28}F_{14}$

Hence, the empirical and molecular formula of the compound is $CH_2F$ and $C_{14}H_{28}F_{14}$ respectively

3 0

3 years ago