Answer: The value of ![[H_{3}O^{+}]](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
is 0.0012 M and ![[OH^{-}]](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D)
is 
.
Explanation:
pH is the negative logarithm of concentration of hydrogen ion.
It is given that pH is 2.89. So, the value of concentration of hydrogen ions is calculated as follows.
![pH = - log [H^{+}]\\2.89 = - log [H^{+}]\\conc. H^{+} = 0.0012 M](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5C2.89%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5Cconc.%20H%5E%7B%2B%7D%20%3D%200.0012%20M)
The relation between pH and pOH value is as follows.
pH + pOH = 14
0.0012 + pOH = 14
pOH = 14 - 0.0012 = 13.99
Now, pOH is the negative logarithm of concentration of hydroxide ions.
Hence, is calculated as follows.
![pOH = - log [OH^{-}]\\13.99 = - log [OH^{-}]\\conc. OH^{-} = 1.02 \times 10^{-14} M](https://tex.z-dn.net/?f=pOH%20%3D%20-%20log%20%5BOH%5E%7B-%7D%5D%5C%5C13.99%20%3D%20-%20log%20%5BOH%5E%7B-%7D%5D%5C%5Cconc.%20OH%5E%7B-%7D%20%3D%201.02%20%5Ctimes%2010%5E%7B-14%7D%20M)
Thus, we can conclude that the value of is 0.0012 M and is .
Answer:
c. 1 tablet
Explanation:
1.04 is rounded to 1 so 1 tablet a day is what he needs
The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.
Answer:
C). Electrostatic attractions between + and - charged ions.
Explanation:
They're electrostatic attractions because it is electrovalent bonding.
Answer:
I think Mg is correct I am not sure
