From what I know personally from learning about this type of subject in the past is that children are more susceptible to the effects of toxic substances more than adults are, certain scientific data specifically indicate that children actually are for all intents and purposes more basically susceptible to toxic exposure than adults because they for the most part have proportionally definitely more intake of food contaminants, basically active developmental processes, basically multiple exposure pathways and really susceptible kind of socio-behavioral activities in a particularly major way.
The specific gravity or relative density of a substance is the ratio of its density to the density of a reference material. The relative density of the concentrated salt solution is 1.044.
Mathematically;
Density of the concentrated salt = mass of salt/volume of salt = 5.222 g/5.000 mL = 1.044 g/mL
In the case of specific gravity, the reference material is always water and water has a density of 1 g/mL.
Hence, specific gravity of the concentrated salt solution =
Density of concentrated salt solution/density of equal volume of water
= 1.044 g/mL/1 g/mL
= 1.044
Note that specific gravity is dimensionless.
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Answer:
120g
Explanation:
Step 1:
We'll begin by writing the balanced equation for the reaction.
Sn + 2HF —> SnF2 + H2
Step 2:
Determination of the number of mole HF needed to react with 3 moles of Sn.
From the balanced equation above,
1 mole of Sn and reacted with 2 moles of HF.
Therefore, 3 moles Sn will react with = 3 x 2 = 6 moles of HF.
Step 3:
Conversion of 6 moles of HF to grams.
Number of mole HF = 6 moles
Molar Mass of HF = 1 + 19 = 20g/mol
Mass of HF =..?
Mass = number of mole x molar Mass
Mass of HF = 6 x 20
Mass of HF = 120g
Therefore, 120g of HF is needed to react with 3 moles of Sn.
Answer:
0.444 mol/L
Explanation:
First step is to find the number of moles of oxalic acid.
n(oxalic acid) = 
Now use the molar ratio to find how many moles of NaOH would be required to neutralize 
of oxalic acid.
n(oxalic acid): n(potassium hydroxide)
1 : 2 (we get this from the balanced equation)
: x
x = 0.0111 mol
Now to calculate what concentration of KOH that would be in 25 mL of water:
