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3 years ago

Al(s) + NiSO4(aq) Balance

Chemistry

1 answer:

irinina [24]3 years ago

8 0

Answer:

$2Al(s) + 3NiSO4 --> Al2(SO4)3 + 3Ni$

Explanation:

This reaction type is a single replacement. The format of a single replacement is:

$A+BC --> B+AC$

A= Al

B= Ni

C= SO

The coefficient 3 for Ni would become a subscript for AC. After you plug those into the reaction you need to count how many of each are on the left side and try to get the same number on the right side. Both sides must be equal to have a balanced equation.

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Name the following compound: HC2H3O2

just olya [345]

Answer:

El ácido acético , denominado sistemáticamente ácido etanoico, es un compuesto orgánico líquido incoloro con la fórmula química CH3COOH (también escrito como CH3CO2H o C2H4O2

Explanation:

Cuando no se diluye, a veces se le llama ácido acético glacial . El vinagre es aproximadamente del 3 al 9% de ácido acético en volumen, lo que hace que el ácido acético sea el componente principal del vinagre, aparte del agua.

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3 years ago

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6. A group of students is performing a simple scientific investigation with baking soda and vinegar. The students place vinegar

natali 33 [55]

Answer:

A. The vinegar and baking soda released a gas. Hope it helps. :)

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3 years ago

BRAINLIEST

PSYCHO15rus [73]

Answer:

This primarily has to do with the balance of energy between the orbitals. The aufbau principle states that the order of energy regarding electrons in the orbitals from lowest to highest is so the electron in the atom will minimalize it's energy. Periods on the periodic table are based on the energy level while the groups have the same amount of valence electrons. The outer orbitals are refered to as shells. The elements are particularly arranged depending on their atomic and molecular orbitals. Valence electrons most determine the chemical properties of an element. The atomic number is based on the number of protons.

3 0

3 years ago

Consider the reaction

SOVA2 [1]

Answer :

(a) The average rate will be:

$\frac{d[Br_2]}{dt}=9.36\times 10^{-5}M/s$

(b) The average rate will be:

$\frac{d[H^+]}{dt}=1.87\times 10^{-4}M/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)$

The expression for rate of reaction :

$\text{Rate of disappearance of }Br^-=-\frac{1}{5}\frac{d[Br^-]}{dt}$

$\text{Rate of disappearance of }BrO_3^-=-\frac{d[BrO_3^-]}{dt}$

$\text{Rate of disappearance of }H^+=-\frac{1}{6}\frac{d[H^+]}{dt}$

$\text{Rate of formation of }Br_2=+\frac{1}{3}\frac{d[Br_2]}{dt}$

$\text{Rate of formation of }H_2O=+\frac{1}{3}\frac{d[H_2O]}{dt}$

Thus, the rate of reaction will be:

$\text{Rate of reaction}=-\frac{1}{5}\frac{d[Br^-]}{dt}=-\frac{d[BrO_3^-]}{dt}=-\frac{1}{6}\frac{d[H^+]}{dt}=+\frac{1}{3}\frac{d[Br_2]}{dt}=+\frac{1}{3}\frac{d[H_2O]}{dt}$