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2 years ago

20 POINTS!!!!!!!!!!!!!!

Biology

2 answers:

daser333 [38]2 years ago

6 0

Answer:

Its a substitution mutation because one of the specific base, G is replaced by A.

Explanation:

ASHA 777 [7]2 years ago

3 0

Answer:

Its a substitution mutation because one of the specific base, G is replaced by A.

This is a Point Mutation because Point mutation brings changes in the structure of a gene because of the substitutions with another base pair. Like in this case, G is substituted by A. In case of frameshift mutations, there is a change in the number of nucleotides due to either insertions or deletions of the nucleotides, which is not in this case.

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Both sound and water waves require a to travel. This means they are

Mekhanik [1.2K]

Answer:

mechanical waves

Explanation:

They require a medium to travel through.

7 0

3 years ago

Read 2 more answers

Gloria is experiencing pain in the upper right portion of her abdomen, has greasy diarrhea, and bleeds excessively when she mens

Volgvan

Bile

Based on the above symptoms, it can be inferred that Gloria lacks bile. Pain in the upper right portion of the abdomen usually corresponds to problems with the liver. The liver produces bile (also known as gall), which is a dark green to yellowish brown fluid that helps most vertebrates with digestion. It increases the absorption of fats and fat-soluble substances such as vitamins A,D,E, and K. It is also necessary for the excretion of bilirubin, which is a byproduct when red blood cells are recycled by the liver.

Bile deficiency can cause the fats in the food to be undigested and these fats end up excreted as part of feces. It can also lead to vitamin deficiency and a gradual build-up of toxins in the liver.

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3 years ago

A complete plant gene containing four introns and five exons is carried on a 6.0-kb DNA fragment. DNA sequencing analysis finds

damaskus [11]

Answer and Explanation:

the total length of the gene is 6,000 base pairs (or) 6.0 kb and it has five exons, four introns and a 1,000 base pair length flanking region for the transcribed region.

Hence, each exon has (1500/5) = 300 by

each intron has (3500/4) = 875 by and

flanking segment (5' and 3') length for the transcribed region would be (1000/2) = 500 bp.

The gene segment is as shown in the 1st diagram attached below

In eukaryotes, transcription takes place in the nucleus which results in the synthesis of hnRNA (heteronuclear ribonucleic acid). This hnRNA (pre-RNA) has both introns and exons, however when it is synthesized or while it is being synthesized the Spliceosomal complex removes introns from hnRNA and becomes converted into mRNA (messenger RNA) in the nucleus itself.

(second diagram explains further)

Now the synthesized mRNA reaches the cytoplasm. So, if mRNA collected from the nucleus and cytoplasm will have the same length of about 2,500 base pairs only. Therefore, after the commencement of northern blot analysis both mRNA will yield the same kind of result and have unique length.

8 0

3 years ago

In the hardy-weinberg equation, p2 + 2pq + q2 = 1. if the dominant allele frequency is 0.8, what percent of the population will

Burka [1]

9467594856840303THG,S.ZGJHFLDHTUI2

7 0

3 years ago

Identify the mitotic phases.

Anna11 [10]

Mitosis consists of four basic phases: prophase, metaphase, anaphase, and telophase. Some textbooks list five, breaking prophase into an early phase (called prophase) and a late phase (called prometaphase). These phases occur in strict sequential order, and cytokinesis - the process of dividing the cell contents to make two new cells - starts in anaphase or telophase.

I gave you a diagram to help put these words into an image.

I hope this helped!!! Have a wonderful day ! :))

4 0

3 years ago

20 POINTS!!!!!!!!!!!!!!​

20 POINTS!!!!!!!!!!!!!!