Valence must be considered and whether the substance is an atom or molecule, for example: 2Na + Cl2=>2 NaCl
Answer:
The standard entropy or reaction ΔS° =+324.6J/mol.K
Explanation:
The reaction is
2H2O(l) → 2H2(g) + O2(g)
Standard Molar Entropies of Selected Substances at 298 K are
Substance S∘ (J/mol⋅K)
H2(g) 130.6
O2(g) 205.0
H2O(g) 188.8
H2O(l) 69.9
The standard entropy of reaction will be obtained from standard entropy of formation as given below
ΔH°= 2(130.6)+(205.0)-2(69.9) (Jol/mol.K)
ΔH°=261.2+205.0-139.8
ΔH°=+324.6Jol/mol.K
The law conservation of mass, because part of the mass can be converted into energy
also, the elements are changing during nuclear reactions, new elements are formed
Answer:
<h2>0.013 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%5C%5C)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{7.81 \times {10}^{21} }{6.02 \times {10}^{23} } \\ = 0.012973...](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B7.81%20%5Ctimes%20%20%7B10%7D%5E%7B21%7D%20%7D%7B6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%3D%200.012973...)
We have the final answer as
<h3>0.013 moles</h3>
Hope this helps you
Answer:
B
Explanation:
u do the math and you will get the answer