Plz answer!!! Due in 10 minutes!!! Will give BRAINLIEST and extra points to first correct answer!!!

Chemistry

2 answers:

Ugo [173]3 years ago

8 0

Answer:

Explanation:

u do the math and you will get the answer

Stella [2.4K]3 years ago

6 0

Answer:

because it would be impossible to get a precise measurement if the mass of the product without the equipment.

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How can professionals increase their levels of stress as a result of personal work habits?

zmey [24]

Answer:

Explanation:

Developing work ethics won't lower your stress although it may make your conscience a little happier. Not B

Not C. Procrastinating just makes things harder. The mountain of things to do is not diminishing at all and your stress knows it.

Not D. Although D is the second best answer, setting goals is not really an action. It is a plan for how to work. But it is not work. Still having a goal is useful.

The answer is A. Just keep hitting what you have to do at a steady pace.

8 0

3 years ago

What is the mass of a sample of alcohol (specific heat = 2.4 J/gC), if it requires 4780 J of heat to raise the temperature by 5.

insens350 [35]

The mass of a sample of alcohol is found to be = m = 367 g

Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.

Explanation:

The Energy of the sample given is q = 4780

We are required to find the mass of alcohol m = ?

Given that,

The specific heat given is represented by = c = 2.4 J/gC

The temperature given is ΔT = 5.43° C

The mass of sample of alcohol can be found as follows,

The formula is c = $\frac{q}{mt}$

We can drive value of m bu shifting m on the left hand side,

m = $\frac{q}{ct}$

mass of alcohol (m) = $\frac{4780}{(2.4)( 5.43)}$

m = 367 g

Therefore, The mass of the given sample of alcohol is

m = 367g

It requires 4780 J of heat to raise the temperature by 5.43 C in the process which yields a mass of 367 g of alcohol.

4 0

4 years ago

Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re

laiz [17]

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.