In order to answer the question we need a picture of some kind
        
                    
             
        
        
        
The answer is -1
Hope this helps!
        
             
        
        
        
Answer:
Yes you are correct
Step-by-step explanation:
 
        
             
        
        
        
Answer:
The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>
                                               √0.45*0.55/600
The right answer is B.
Step-by-step explanation:
According to the given data we have the following:
sample size, h=600
probability against increase tax p=0.45
The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.
We find that P(P>360/600)=P(P>0.6)
The sample proposition of p is approximately normally distributed mith mean p=0.45
standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600
If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)
Now, P(P>0.6)=P(<u>P-P</u>   >     <u>0.6-0.45)</u>
                              σ          √0.45*0.55/600
=P(Z> <u>0.6-0.45)</u>
        √0.45*0.55/600
 
        
             
        
        
        
Answer:
its C
Step-by-step explanation: