Question

Identify the center and radius of the circle (x-7)^2+(y-11)^2=36

Answer 1

Answer:

Centre is $(7,11)$

Radius is $6$

Step-by-step explanation:

The general equation for a circle is written in the form $(x-a)^2+(y-b)^2=r^2$ , where $(a,b)$ is the centre of the circle, and $r$ is the radius.

For your circle, $(x-7)^2+(y-11)=36$, we can compare it with the general equation to find the centre and radius.

$-a = -7$

$-b = -11$

$r^2 = 36$

Therefore, $a=7$, $b=11$ and $r=6$.

Centre at $(a,b)$ which is $(7,11)$ .