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elena55 [62]
3 years ago
5

A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the

square is StartFraction pi r squared Over 4 r squared EndFraction or StartFraction pi Over 4 EndFraction.
A cylinder is inside of a square prism. The height of the cylinder is h and the radius is r. The base length of the pyramid is 2 r.

Since the area of the circle is StartFraction pi Over 4 EndFraction the area of the square, the volume of the cylinder equals

StartFraction pi Over 2 EndFraction the volume of the prism or StartFraction pi Over 2 EndFraction(2r)(h) or πrh.
StartFraction pi Over 2 EndFraction the volume of the prism or StartFraction pi Over 2 EndFraction(4r2)(h) or 2πrh.
StartFraction pi Over 4 EndFraction the volume of the prism or StartFraction pi Over 4 EndFraction(2r)(h) or StartFraction pi Over 4 EndFractionr2h.
StartFraction pi Over 4 EndFraction the volume of the prism or StartFraction pi Over 4 EndFraction(4r2)(h) or Pir2h.
Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

Eva8 [605]3 years ago
3 0

Answer:

d

Step-by-step explanation:

i took the test

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Help me out please and thank you
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<h3>Answer: 1</h3>

========================================================

Explanation:

We're given the height in relation to base BC, so we need to find the length of this base. This is the same as finding the distance from B to C.

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Coincidentally, the base and height are the same. This won't always be the case.

Now we can find the area of the triangle

A = \text{Area of triangle}\\\\A = \frac{1}{2}*\text{Base}*\text{Height}\\\\A = \frac{1}{2}*\sqrt{2}*\sqrt{2}\\\\A = \frac{1}{2}*\sqrt{2*2}\\\\A = \frac{1}{2}*\sqrt{4}\\\\A = \frac{1}{2}*2\\\\A = 1\\\\

The area of the triangle is 1 square unit.

See diagram below.

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3 years ago
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