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elena55 [62]
3 years ago
5

A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the

square is StartFraction pi r squared Over 4 r squared EndFraction or StartFraction pi Over 4 EndFraction.
A cylinder is inside of a square prism. The height of the cylinder is h and the radius is r. The base length of the pyramid is 2 r.

Since the area of the circle is StartFraction pi Over 4 EndFraction the area of the square, the volume of the cylinder equals

StartFraction pi Over 2 EndFraction the volume of the prism or StartFraction pi Over 2 EndFraction(2r)(h) or πrh.
StartFraction pi Over 2 EndFraction the volume of the prism or StartFraction pi Over 2 EndFraction(4r2)(h) or 2πrh.
StartFraction pi Over 4 EndFraction the volume of the prism or StartFraction pi Over 4 EndFraction(2r)(h) or StartFraction pi Over 4 EndFractionr2h.
StartFraction pi Over 4 EndFraction the volume of the prism or StartFraction pi Over 4 EndFraction(4r2)(h) or Pir2h.
Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

Eva8 [605]3 years ago
3 0

Answer:

d

Step-by-step explanation:

i took the test

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What polynomial identity should be used to prove that 35 = 8 + 27
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Answer:

Sum of cubes identity should be used to prove 35 =3+27

Step-by-step explanation:

Prove that : 35 = 8 +27

Polynomial identities are just equations that are true, but identities are particularly useful for showing the relationship between two apparently unrelated expressions.

Sum of the cubes identity:

a^3+b^3=(a+b)(a^2-ab+b^2)

Take RHS

8+ 27

We can write 8 as 2 \times 2 \times 2 = 2^3 and 27 as 3 \times 3 \times 3 = 3^3.

then;

8+27 = 2^3+3^3

Now, use the sum of cubes identity;

here a =2 and b = 3

2^3+3^3 = (2+3)(2^2-2\cdot 3+3^2)

or

2^3+3^3 = (5)(4-6+9) = 5 \cdot 7 = 35 = LHS    proved!

therefore, the Sum of cubes polynomial identity should be used to prove that 35 = 8 +27

4 0
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