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Bezzdna [24]
3 years ago
15

Miguel cut 1/4 from a round pie. Mariah cut a piece from the same pie an angle measure of 60 ° . who cut a larger piece

Mathematics
1 answer:
gogolik [260]3 years ago
4 0
There are 360 degrees in a circle. 1/4 * 360 = 90 degrees

90 degrees > 60 degrees meaning Miguel cut the larger piece by 30 degrees
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Consider the following figure.
Karolina [17]

Answer:

BD = 16

Step-by-step explanation:

By applying mean proportional theorem in the given right triangles,

\frac{AD}{BD}=\frac{BD}{CD}

AD × CD = BD²

8 × 32 = BD²

BD = √256

BD = 16

Therefore, measure of side BD = 16 units.

4 0
2 years ago
Find the two numbers whose deference is 10 and sum is 34​
mezya [45]

Answer:

the correct answer is 22 and 12

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
I need to solve this system of equations, how do I do that?<br> 3x-4y=20<br> y=3/4x-5
Paha777 [63]

Answer:

Is is Infinitely many solutions so 0=0

<em><u>Step-by-step explanation:</u></em>

<h3>First we have to rearrange/simplify the equations:</h3>

Equation 1: 4y - 3x = -20

Equation (2):  y - 3x/4  = -5

<h3>Then you remove the fractions by multiplication: </h3>

Multiply equation (2) by 4

<h3>The Equations now look like this: </h3>

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

<h3>Solve for y on Equation (2):</h3>

y = <u><em>3x/4 - 5</em></u>

<h3>Then plug in this for the y in Equation 1 and then solve:</h3>

4•(<u><em>3x/4-5</em></u>) - 3x = -20

Therefore the answer leads to:

Infinitely many solutions, 0=0

Hope this helped :')

4 0
2 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
Given: ∆ABC, AB = CB
SCORPION-xisa [38]
Angle ABC = 48
Angle PBC = 24
Angle A + Angle C = 180-24.  Angle A = Angle C
Angle C = 132/2 = 66
Angle PCD = 66-24 = 42 degrees
4 0
3 years ago
Read 2 more answers
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