Y-4= -3(x-3)
First you'll distribute the -3(x-3) and you should get -3x+9 (a negative divided by a negative is a positive)
So your new equation will be y-4=-3x+9. Next you'll get rid of the -4 y adding 4 on both sides of the equation. So you should get y=-3x+13. So points you could use is <span><span>(<span>0,13</span>)</span>,<span>(<span>1,10</span>)</span>,<span>(<span>2,7</span>)</span></span><span />
Answer
-1
Step-by-step explanation:
Answer:
a) The differential equation for the velocity is given by
(dv/dt) = k(250 - v)
b) v(t) = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾
With units of km/h
Step-by-step explanation:
Acceleration, a ∝ (250 - v)
But acceleration is widely given as dv/dt
(dv/dt) ∝ (250 - v)
(dv/dt) = k(250 - v)
where k = constant of proportionality
(dv/dt) = k(250 - v)
b) (dv/dt) = k(250 - v)
dv/(250 - v) = k dt
∫ dv/(250 - v) = ∫ k dt
- In (250 - v) = kt + c (where c is the constant of integration)
v(0) = 0; meaning, at t = 0, v = 0
- In 250 = 0 + C
c = - In 250 = - 5.52
- In (250 - v) = kt - 5.52
In (250 - v) = 5.52 - kt
250 - v = e⁽⁵•⁵² ⁻ ᵏᵗ⁾
v = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾
With units of km/h
i hope this work for you
and sory if im wrang
Answer:
Step-by-step explanation:
- <em>
</em><u><em>Question</em></u><em>:</em>
- <em>How many kilometers does Daisy have left to reach the picnic area?
</em>
<u>Given</u>
<u>Let the distance be x, then</u>
- 0.6x = 18
- x = 18/0.6
- x = 30 km
<u>Remaining distance is:</u>
