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o-na [289]
3 years ago
8

Um ônibus escola pode transporta ete 32 alunos quantos ônibus iguais são necessários para transportar 1 120 alunos​

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

sorry i dont know what the answer is

Step-by-step explanation:

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Find the cost per roll if a bag of five lunch rolls is $2.50.
Andru [333]
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50 </em></u></h3><h3><u><em> 2 lunches = $5.00 (2.50x2) </em></u></h3><h3><u><em> 3 lunches =$7.50 </em></u></h3><h3><u><em> 4 lunches =$10.00 </em></u></h3><h3><u><em> 5 lunches= $12.50 </em></u></h3><h3><u><em> Just add $2.50</em></u></h3>
5 0
3 years ago
What is the equation of the line that is parallel to 8x-5y=2 and goes through the point (-5,-2)
Stella [2.4K]

Answer:

8x - 5y = - 30

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 8x - 5y = 2 into this form

Subtract 8x from both sides

- 5y = - 8x + 2 ( divide all terms by - 5 )

y = \frac{8}{5} x - \frac{2}{5} ← in slope- intercept form

with slope m = \frac{8}{5}

• Parallel lines have equal slopes, hence

y = \frac{8}{5} x + c ← is the partial equation of the parallel line

To find c substitute (- 5, - 2) into the partial equation

- 2 = - 8 + c ⇒ c = - 2 + 8 = 6

y = \frac{8}{5} x + 6 ← in slope- intercept form

Multiply through by 5

5y = 8x + 30 ( subtract 5y from both sides )

0 = 8x - 5y + 30 ( subtract 30 from both sides )

8x - 5y = - 30 ← in standard form

3 0
3 years ago
Please help with geometry
Margarita [4]

Step-by-step explanation:

a) gradient= y2-y1/x2-x1

gradient of AB:

gradient=-4-1/2-3

=-5/-1

=5

gradient of BC:

=-5+4/7-2

=-1/5

b) as the priduct of both gradient is -1 ,both lines are perpendicular.

c) as we have seen lines are perpendicular so it is a right angled triangle.

8 0
3 years ago
What is 140 1/8 in radical form?
posledela
140 1/8 can not be expressed in radical form because it neither has an exponent or a square root. Unless if 140 is raised to the power of 1/8, then that can be.
8 0
3 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
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