Answer:
speed=d/t
let him cover x distance while walking
running d=4.5-x
s1=x/0.5 km/hr....(1)
s2=4.5-x//5/12.....(2)
atq.....s2=2+s1
s1=2x
s2=54-12x/5
by eqn 1 and 2
s1+s2=2x+54-12x/5
putting value of s2
s1+2+s1=2x+54-12x/5....taking LCM =5
10s1+10= 10x+54-12x
as s1=2x
10s1+10= -2x+54
10s1+10=-s1+54
11s1=44
speed when walking=4km/hr
I don’t know to be honest
Y = 3x. the y axis goes up by an interval of 3.
sara speed is half of Jeanette's so if jeanette ran 7 miles then her walking speed is 3.5MPH and sense she is 7 miles ahed sara is 10.5 miles behind... 3.5MPH which is jeanette speed is double than sara so 3.5/2 is 1.75MPH... Saras walking speed is 1.75MPH
Answer:
10it is 10
Step-by-step explanation:
