Can someone plz help me plzzzz!!!!

The radius, R, of a sphere, is 6.3cm. Calculate the sphere's volume, V.

sleet_krkn [62]

Answer:

V = 1046.9

Step-by-step explanation:

The equation for volume is (4/3)pi r^3

substitute 3.14 in for pi and 6.3 in for r so (4/3)*3.14*6.3^3

6 0

2 years ago

Find the value of x. Using trig

scoundrel [369]

Hi there! We can find the value of x by using this equation.

$\large \boxed{tanx = \frac{19}{23} }$

If you remember, tanx = opposite/adjacent. We focus on the angle x currently.

Now that you might wanna ask if there is a value of x that makes 19/23. The answer is yes but in decimal.

$\large{arctan( \frac{19}{23} )} = x$

You might wanna put arctan(19/23) in a calculator since it's not really possible to get the square root like value by yourself.

arctan(19/23) is 0.69

Then we round up and get 0.7

Hence, the value of x ≈ 0.7

Answer

x ≈ 0.7 (rounded)

Questions can be asked through comment.

Hope it helps, and Happy Learning! :)

4 0

3 years ago

Find the measure of angle JML.

Tanya [424]

Answer:

110°

Step-by-step explanation:

8 0

3 years ago

Ratio of 200m and 1km.

kkurt [141]

Answer:

1 : 5

Step-by-step explanation:

→ Convert 1km into metres

1000

→ Put in ratio format

200 : 1000

→ Simplify

1 : 5

8 0

3 years ago

A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to

alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

$-1.152 < \mu_{safe1}-\mu_{safe2}$

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution

Let put some notation

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference $d_i=x_i-y_i$ and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093$

The next step is calculate the degrees of freedom given by:

$df=n-1=9-1=8$

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.