All categories

3 years ago

14. The equation of the line that passes through the

Mathematics

1 answer:

KIM [24]3 years ago

3 0

Answer:

5. y = -x

Step-by-step explanation:

First, you need to find the slope of the line.

$m = \frac{2 - (-3)}{-2 - 3} = \frac{5}{-5} = -1$

Now, using either point substitute into the point-slope form for a line:

$y - y_{1} = m(x - x_{1} )$

Using (-2,2) for $(x_{1} , y_{1} )$ we get y - 2 = -1(x +2)

y - 2 = -x - 2

y = -x

Answer 5 is the correct answer

You might be interested in

A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so

otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

$\hat{p}=\dfrac{25}{123}\approx0.203252$

Critical value for 95% confidence interval : $z_{\alpha/2}=1.96$

Confidence interval for population :

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}$

$0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)$

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0

4 years ago

Which of the following equations represents a nonlinear function?

Ainat [17]

Y=square root of x

All the others would be a straight line with an unchanging slope (meaning they're linear). Y=rootx is not linear.
I hope this Helps!

8 0

3 years ago

What is the answer to this

Arisa [49]

Answer:

x = 20, <S = 47 degrees, <P = 131 degrees

Step-by-step explanation:

27 + x + 119 + 63 + 3x + 71 = 360

4x + 280 = 360

4x = 80

x = 20

<S = 27 + x = 27 + 20 = 47 degrees

<P = 3x + 71 = 3(20) + 71 = 131 degrees

5 0

3 years ago

People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear

Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

α: 0.05

Left critical value: $t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306$

Right critical value: $t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306$

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

X[bar]= 23

S= 3

$t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3$

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

7 0

3 years ago

On a hiking trip, Melissa notes that she hikes about 16 kilometers every 2.5 hours. If she continues at this rate, about how man

svp [43]

Answer:

so if she hike 12 km every 4 hours, how many km could she hike in 6 hours.

first u have to find the equation. 12 km=4hours

? =6hours

and then you have to multiply 12 km by 6 hours and divide the results by 4 which is 12×6÷4. the final answer will be 18 kilometers.

Step-by-step explanation:

Sorry if its wrong

5 0

3 years ago