Question

Question: The graph of a second-order polynomial is shown below, and the intercepts with the axes are marked. Explain how you can use the graph to write the polynomial as a product of linear factors (x-a)(x-b). Be sure to state the values of a and b. NEED HELP ASAP​

Answer 1

Hello!

Here we are given a second-order polynomial, and the root form of the function.

$y=a(x-c)(x-d)$

Where c and d are zeros of the function, which is where the graph intersects the x-axis.

$y=a(x+4)(x-3)$

$-6=a(2+4)(2-3)$

$-6=-6a$

$a=1$

Therefore, the equation of this polynomial would be $y=(x+4)(x-3)$, and the values of a and b would be the x-intercepts.

Hope this helps!