Answer:
9. This is because you have to add 13 to -4, which gives you positive 9. Hope this helped!
Answer:
this hurts my brain x_x my non-existent brain....
Given:
An athlete who makes
laps in 3 mins 45 seconds on a 400m field.
To find:
The speed of the athlete in m/s.
Solution:
We know that,
Distance covered in 1 lap = 400 m
Distance covered in
laps =
m
=
m
=
m
We know that,
1 minute = 60 seconds
3 minutes = 180 seconds
3 minutes 45 second = 180 + 45 seconds
= 225 second
The speed of the athlete is:
![Speed=\dfrac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%3D%5Cdfrac%7BDistance%7D%7BTime%7D)
![Speed=\dfrac{1900}{225}](https://tex.z-dn.net/?f=Speed%3D%5Cdfrac%7B1900%7D%7B225%7D)
![Speed\approx 8.44](https://tex.z-dn.net/?f=Speed%5Capprox%208.44)
Therefore, the speed of the athlete is about 8.44 m/s.
Answer:
3 is the correct answer
u can find common ratio by dividing a specific term in GP by its preceding term. ...just as here
4/(4/3) = 3
also 12/4 = 3
also 36 /12 = 3
hence the common ratio for this GP is 3
hope it helped
Step-by-step explanation:
Answer:
The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.
Step-by-step explanation:
Confidence interval normal
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1 - 0.96}{2} = 0.02](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1%20-%200.96%7D%7B2%7D%20%3D%200.02)
Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.054.
Now, find the margin of error M as such
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 2.054\frac{54}{\sqrt{430}} = 5.35](https://tex.z-dn.net/?f=M%20%3D%202.054%5Cfrac%7B54%7D%7B%5Csqrt%7B430%7D%7D%20%3D%205.35)
The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes
The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes
The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.