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Alex777 [14]
3 years ago
8

Next time, the rabbit from the previous problem started at 10. Where on the number line can he be after the same three jumps?

Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

13

Step-by-step explanation:

If the rabbit started at 10 you would add 3 to 10 and get 13.

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Jobisdone [24]
76, 84, 93, 67, 82, 87, & 76

The mean is just the middle number of the data set,

Start by rewriting the set in order from smallest to biggest:
67, 76, 76, 82, 84, 87, 93

Determine which is the number in the middle,
67, 76, 76, *82*, 84, 87, 93

So, in this case, the median is 82.
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3 years ago
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Select the assumption necessary to start an indirect proof of the statement. If 3a+7 < 28, then a<7.
pashok25 [27]
When applying indirect proofs, we assume the negation of the conclusion is true, and show that this assumption would lead to nonsense, or contradiction.

In our case we assume a is not smaller than 7, that is we assume a≥7.

a≥7 then, multiplying both sides by 3:
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3a+7≥28,

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So our assumption is wrong, which means the opposite of it is correct.


Answer: assume a≥7
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2 years ago
What is the surface area of the prism in square inches?
astra-53 [7]

Answer:

4 inches deep, 5 inches high and 15 inches across

8 0
3 years ago
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Plz help I will thank u and mark u as branilyest
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 number 9 =al you have to do is one and 7 eighths =9 so your sum will be 10 and 7 eighths.

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2 years ago
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G(x) = -2x^3 – 15x^2 + 36x
shusha [124]

Consider the function G(x) = -2x^3 - 15x^2 + 36x. First, factor it:

G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).

The x-intercepts are at points \left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).

1. From the attached graph you can see that

  • function is positive for x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);
  • function is negative for x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).

2. Since

G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x) the function is neither even nor odd.

3. The domain is x\in (-\infty,\infty), the range is y\in (-\infty,\infty).

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