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ra1l [238]
2 years ago
12

Jace is making a water play table from a triangular table top. He sketched a dotted line to show where he wants to add a circula

r water bowl. It should go all the way to the edges of the table as shown. A circle is inscribed within triangle A B C. The length of A B is 3.5 feet, the length of B C is 4 feet, and the length of A C is 2 feet. Angle A B C is 30 degrees and angle A C B is 60 degrees. What should Jace do first to find the exact location of the center of the circular water bowl? He should find the midpoint of each edge of the table. He should bisect each of the angles at the vertices of the triangular table top. He should draw perpendicular lines through any point along the edges of the table. He should draw perpendicular line segments from each corner to the opposite edge of the table.
Mathematics
2 answers:
Svet_ta [14]2 years ago
6 0

Answer:

B-He should bisect each of the angles at the vertices of the triangular table top.

Step-by-step explanation:

Natasha2012 [34]2 years ago
4 0

B. He should bisect each of the angles at the vertices of the triangular table top.

Good luck on the exam :)

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I'm assuming each tickmark is 1/4 = 0.25

If that assumption is correct, then going one tickmark to the left of -3/4 lands you on -4/4 which simplifies to -1.

So -1 is one tickmark to the left of -3/4

Again, this all hinges on the assumption that each tickmark is 1/4 a unit away from its neighbor.

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Answer:

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Step-by-step explanation:

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A TV has a listed price of $885.98 before tax. If the sales tax rate is 8.5%, find the total cost of the TV with sales tax
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8 0
3 years ago
Set up an equation and solve the following problem.
nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

<u>Again</u>

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

<u>For Dave</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, t = \dfrac{\textrm d miles}{\textrm s miph}

Or, t = \dfrac{\textrm 210 miles}{\textrm s miph}

<u>For Kent</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, T = \dfrac{\textrm D miles}{\textrm S miph}

Or, T = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

∵ Time taken by both is same

So, t = T

Or,  \dfrac{\textrm 210 miles}{\textrm s miph} = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = \dfrac{840}{20}

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0
3 years ago
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