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jekas [21]
4 years ago
8

What value of r is a solution to this equation 5r=15

Mathematics
2 answers:
Vilka [71]4 years ago
4 0

Answer:

3

Step-by-step explanation:

inysia [295]4 years ago
3 0
3 is the answer for r
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Just divide 3.5 with 100 so it would be 0.035
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Using t=tanx/2, write an expression for sinx and cosx in terms of t.
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Assume 0 < <em>x</em>/2 < <em>π</em>/2. Then

tan²(<em>x</em>/2) + 1 = sec²(<em>x</em>/2)   ===>   sec(<em>x</em>/2) = √(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - <em>t</em> ²)

We also know that

sin²(<em>x</em>/2) + cos²(<em>x</em>/2) = 1   ===>   sin(<em>x</em>/2) = √(1 - cos²(<em>x</em>/2))

Recall the double angle identities:

cos(<em>x</em>) = 2 cos²(<em>x</em>/2) - 1

sin(<em>x</em>) = 2 sin(<em>x</em>/2) cos(<em>x</em>/2)

Then

cos(<em>x</em>) = 2/(1 - <em>t</em> ²) - 1 = (1 + <em>t</em> ²)/(1 - <em>t</em> ²)

sin(<em>x</em>) = 2 √(1 - 1/(1 - <em>t</em> ²)) / √(1 - <em>t</em> ²) = 2<em>t</em>/(1 - <em>t</em> ²)

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Ganezh [65]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: ax^2 + bx + c = 0

Quadratic Formula: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

Given our Equation: g(x) = x^2 - 2x - 4

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Plug the values into the equation and solve.

<h3>Solve</h3>
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Sixth graders can have 4 groups of 4
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