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Leokris [45]
2 years ago
10

plss answer what do yo call the substance from the male body that travel to the female body to make children​

Physics
2 answers:
grin007 [14]2 years ago
8 0

Answer:

It is called sperm

Explanation:

uysha [10]2 years ago
7 0

Answer:

sperms or semen

Explanation:

sorry if i got it wrong

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For the equilibrium reaction N2O4(g) ⇀↽ 2 NO2(g) taking place inside a sealed container fitted with a piston, predict the effect
Butoxors [25]

Answer:

4. The equilibrium will shift to favor formation of NO2(g)

Explanation:

According to La Chatalier's Principle which states that when an equilibrium system undergoes changes either in temperature, volume or concentration; there will be in a change in the system in order to reach equilibrium.

From the above equation,

N2O4(g) ⇀↽ 2 NO2(g)

From the above reaction, there are 2 moles of gaseous product on the left and 1 mole of gaseous reactant.

Therefore, there are more moles of gases in the left hand side than the right hand side.

Because a decrease in volume favors the direction that produces fewer moles, an increase in volume will therefore shift this system towards the side with more moles of gases that is, more products are formed hence, this system will shift to right and produce more moles of products i.e more NO2(g) formed.

6 0
2 years ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
3 years ago
What force is needed to accelerate 300kg rock as a rste of 4m/s​
Natali [406]

Answer:

60 maybe

Explanation:

4 0
3 years ago
Read 2 more answers
que ventajas e inconvenientes tienen las energias renovables, el agua del mar, agua embalzada, el sol, el viento
ahrayia [7]

Answer:

Ventajas ambientales:

La principal ventaja es la prácticamente es nula la emisión de gases de efecto invernadero (GEI).

* Ayudan a disminuir enfermedades relacionadas con la contaminación.

* No necesitan grandes cantidades de agua para su funcionamiento.

* No crean problemas de basura difíciles de resolver, como la eliminación de residuos nucleares o escorias.

Ventajas económicas:

*Generación de empleos directos (trabajadores de la construcción, desarrolladores, fabricantes de equipo, diseñadores, instaladores, financieros).

* Competencia y reducción de precios de las generadoras tradicionales por tener un nuevo competidor, que asegure confiabilidad del servicio.

ENERGÍA SOLAR INCONVENIENTES:

La instalación de paneles solares en casas o industrias no es barato, además no todas las vivienda pueden instalarse este tipo de paneles. La legislación en cuanto al uso de los paneles solares no es la misma en todo el mundo.

ENERGÍA EÓLICA INCONVENIENTES:

La creación de parques eólicos es muy cara, además hay colectivos que se opinen a la instalación de parques eólicos en tierra porque opinan que afea el paisaje y es peligrosos para las aves que chocan al volar cerca de las hélices de los generadores eólicos.

ENERGÍA DE LAS MAREAS INCONVENIENTES:

El movimiento de las mareas mueve las turbinas. El movimiento de las mareas es capaz de mover turbinas, pero para ello hay que construir represas o aluviones.

Entre los inconvenientes está que la construcción de aluviones es muy cara. Hay oposición de grupos ecologistas que destacan que esta energía puede tener un impacto negativo sobre la fauna acuática. La energía de las mareas puede reducir el flujo de las mareas e impedir el flujo de aguas residuales al mar.

Explanation:

5 0
3 years ago
A current of 4.00 mA flows through a copper wire. The wire has an initial diameter of 4.00 mm which gradually tapers to a diamet
lesya692 [45]

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

  • <em>Current flowing in the wire, I = 4.00 mA</em>
  • <em>Initial diameter of the wire, d₁ = 4 mm = 0.004 m</em>
  • <em>Final diameter of the wire, d₂ = 1 mm = 0.001 m</em>
  • <em>Length of wire, L = 2.00 m</em>
  • <em>Density of electron in the copper, n = 8.5 x 10²⁸ /m³</em>

<em />

The initial area of the copper wire;

A_1 = \frac{\pi d^2}{4} = \frac{\pi \times (0.004)^2}{4} =1.257\times 10^{-5} \ m^2

The final area of the copper wire;

A_2 = \frac{\pi d^2}{4} = \frac{\pi (0.001)^2}{4} = 7.86\times 10^{-7} \ m^2

The initial drift velocity of the electrons is calculated as;

v_d_1 = \frac{I}{nqA_1} \\\\v_d_1 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 1.257\times 10^{-5}} \\\\v_d_1 = 2.34 \times 10^{-8} \ m/s

The final drift velocity of the electrons is calculated as;

v_d_2 = \frac{I}{nqA_2} \\\\v_d_2 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 7.86\times 10^{-7}} \\\\v_d_2 = 3.74\times 10^{-7}  \ m/s

The change in the mean drift velocity is calculated as;

\Delta v = v_d_2 -v_d_1\\\\\Delta v = 3.74\times 10^{-7} \ m/s \ -\ 2.34 \times 10^{-8} \ m/s = 3.506\times 10^{-7} \ m/s

The time of motion of electrons for the initial wire diameter is calculated as;

t_1 = \frac{L}{v_d_1} \\\\t_1 = \frac{2}{2.34\times 10^{-8}} \\\\t_1 = 8.547\times 10^{7} \ s

The time of motion of electrons for the final wire diameter is calculated as;

t_2 = \frac{L}{v_d_1} \\\\t_2= \frac{2}{3.74 \times 10^{-7}} \\\\t_2 = 5.348 \times 10^{6} \ s

The average acceleration of the electrons is calculated as;

a = \frac{\Delta v}{\Delta t} \\\\a = \frac{3.506 \times 10^{-7} }{(8.547\times 10^7)- (5.348\times 10^6)} \\\\a = 4.38\times 10^{-15} \ m/s^2

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

Learn more here: brainly.com/question/22406248

7 0
2 years ago
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