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alexdok [17]
3 years ago
9

A ball is thrown straight upward and rises to a maximum height of 18.0 m above its launch point. at what height above its launch

point has the speed of the ball decreased to one-half of its initial value?
Physics
1 answer:
slava [35]3 years ago
5 0

A ball is thrown straight upward and rises to a maximum height of 18.0 m

above its launch point. at what height above its launch point has the

speed of the ball decreased to one-half of its initial value?

-----------------------

kinematic equation

v^2=u^2-2as; v0=,s=18,a=-10m/s/s

u=root 360


(u/2)^2=u^2-2as

=>s=13.5m

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Answer:

dJ = 1.7 m

Explanation:

The Equation of the Balancing the moments in the center of the seesaw  is like this:

∑Mo = 0

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Mo : moment in the o point ( N*m)

F  : Force ( N)

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Data

mA = 60 kg : mass of the Anna

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dA = 2 m : Distance from Anna to the center of the seesaw

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Calculation of the distance from Jon to the center of the seesaw  (dJ)

∑Mo = 0   WA : Ana's weight   , WJ : Jon's weight

W = m*g

(WA)(dA) - (WJ) (dJ) = 0

(mA*g)(dA) - (mJ*g)(dJ) = 0

We divide by g the equation:

(mA)(dA) - (mJ)(dJ)= 0

(mA)(dA) = (mJ)(dJ)

d_{J} = \frac{m_{A} *d_{A}}{m_{J}}

d_{J} = \frac{60 kg *2 m}{70 kg}

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5 0
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A rubber band has potential energy of 5 J. If the spring constant of the rubber band is 50 N/m, what is the displacement of the
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To determine the displacement, since we are given the potential energy, we use the equation for potential energy. For a spring, it is one-half the product of the spring constant and the square of the displacement. We do as follows:

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The correct answer is

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