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IRINA_888 [86]
3 years ago
6

ASAP FIRST TO ANSWER CORRECTLY WILL BE BRAINLIEST

Physics
1 answer:
FromTheMoon [43]3 years ago
8 0

Answer:

1) divergent

2) Diverge

3) Himalayan

PLZ make me the brainliest

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What is the kinetic energy of a 144.1 kg man running along at 3.44 m/s?
Novay_Z [31]
The equation of kinetic energy is K =  \frac{1}{2} * mv^2, where v = velocity and m= mass. 

So, 

144.1 kg * 11.56 m/s * 1/2 = 832.898
7 0
3 years ago
The paper dielectric in a paper-and-foil capacitor is 0.0800 mm thick. Its dielectric constant is 2.50, and its dielectric stren
jeka94

Answer:

a) 0.723 m²

b) 2000V

Explanation:

Given that

Thickness of the capacitor, d = 0.08*10^-3 m

Dielectric constant of the capacitor, k = 2.5

Dielectric strength of the capacitor, E = 50*10^6

Capacitance of the capacitor, C = 0.2*10^-6

Permittivity of free space, E• = 8.85*10^-12

a)

The area, A is given by the formula

A = (C * d) / (k * E•)

A = (0.2*10^-6 * 0.08*10^-3) / (2.5 * 8.85*10^-12)

A = 1.6*10^-11 / 2.213*10^-11

A = 0.723 m²

b)

Potencial difference, V is given by the formula

V = E * d

V = 1/2 * 50*10^6 * 0.08*10^-3

V = 1/2 * 4000

V = 2000 V

8 0
4 years ago
What is meant by lateral inversion​
grandymaker [24]

Answer:

Explanation:

Lateral inversion is a phenomenon where the right seems to be on the left and left seems to be on the right.It occurs due to the direction is reflecting of a direct surface.An example of this is a mirror/window.A mirror is a better example to explain this! Hope this helps lemme know if u dont

4 0
3 years ago
A 12-V car battery supported a current of 150 mA to bulb calculate the power absorbed by the bulb over an interval of 20 mintues
ASHA 777 [7]

Answer:

  • +1.8W
  • 2,160J

Explanation:

First, we need to solve for the power absorbed by the bulb.

Formula [ p = vi ]

p = 12 * 150 * 10^-3

p = +1.8W

Second, we can solve for the power aborbed in a interval of 20 minutes.

Formula [ e = vit ]

e = 12 * 150 * 10^-3 * 20 * 60

e = 2,160J

Just a note that "20 * 60" represents the time given in seconds.

Best of Luck!

7 0
2 years ago
To form a hydrogen atom, a proton is fixed at a point and an electron is brought from far away to a distance of 0.529 ✕ 10−10 m,
Elodia [21]
1) First of all, let's calculate the potential difference between the initial point (infinite) and the final point (d=0.529x10-10 m) of the electron.
This is given by:
\Delta V =- \int\limits^{d}_{\infty} {E} \, dr
Where E is the electric field generated by the proton, which is
E=k_e  \frac{q}{r^2} 
where k_e=8.99\cdot10^9~Nm^2C^{-2} is the Coulomb constant and q=1.6\cdot10^{-19}~C is the proton charge.
Replacing the electric field formula inside the integral, we obtain
\Delta V =- \int\limits^{d}_{\infty} {k_e  \frac{q}{r^2} } \, dr = k_e  \frac{q}{d}= 27~V

2) Then, we can calculate the work done by the electric field to move the electron (charge q_e=-1.6\cdot10^{-19}C) through this \Delta V. The work is given by
W=-q_e \Delta V = - (-1.6\cdot10^{-19}C) (27V)=4.35\cdot10^{-18}~J

5 0
3 years ago
Read 2 more answers
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