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Answer:
2.85 m
Explanation:
From trigonometry,
Cosine = Adjacent/Hypotenuse
Assuming, The wall, the ladder and the ladder forms a right angle triangle as shown in fig 1, in the diagram attached below.
cos∅ = a/H....................... Equation 1
Where ∅ = Angle the ladder makes with the horizontal, a = The horizontal distance from the bottom of the ladder to the wall, H = The length of the ladder.
make a the subject of the equation
a = cos∅(H)..................... Equation 1
Given: ∅ = 68 °, H = 7.6 m.
Substitute into equation 2
a = cos(68)×7.6
a = 0.375×7.6
a = 2.85 m.
Hence the horizontal distance from the bottom of the ladder to the wall = 2.85 m
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
Answer:
Find the attachments for complete solution
The answer would be erin out of all of them thank me later :)
