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3 years ago

What is the meaning of overall charge.

1 answer:

8 0

Suppose you have a box that is a cubic meter. It is made of copper. It is solid. It has 1000000 extra electrons. It has an overall charge of 1000000 electrons that are spread all over it's volume.

It means the excess or deficiency of the number of electrons on a body capable taking on or giving up electrons. When the electrons are taken on or given up, there is no chemical change.

I usually try and answer this kind of question by an example because I don't think the definition is always clear on it's own.

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A 2,100 kg car drives east toward a 55 kg shopping cart that has a velocity of 0.50 m/s west. The two objects collide, giving th

Marta_Voda [28]

Answer:

C. 6.68m/s east

Explanation:

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6 0

2 years ago

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List out the fundamental and derived units

mrs_skeptik [129]

Derived Units Table: The Table Shows the List of Derived Units
Quantity Formula SI Derived Unit
Force Mass x Acceleration
Work Energy Force x Displacement Power/Time Kg. m.s-2
Pressure, Stress Force/Area Kg.m-1.s-2
Current density J = I/A A.m-2

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2 years ago

The energy of the electron in Hydrogen atom can be shown to be given by En = -13.6/n^2 eV, where n represents the principal quan

Tpy6a [65]

Answer:

This represents radiation in ultra-violet region .

Explanation:

Energy of the orbit where n = 3 is given as follows

$E_3 =- \frac{13.6 }{3^2}$

$E_3 =- \frac{13.6 }{9}$ = -1.511 eV

Energy of the orbit where n = 1 is given as follows

$E_1 =- \frac{13.6 }{1^2}$

$E_1 =- \frac{13.6 }{1}$ = 13.6 eV

Difference of [tex]E_3 and [tex]E_1 = - 1.511+ 13.6

= 12.089 eV.

The wavelength of light having this energy in nm is given by the expression as follows

Wavelength in nm = 1244 / energy in eV

= 1244 / 12.089

= 102.90 nm

This represents radiation in ultra-violet region .

8 0

2 years ago

A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio

Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to $F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N$

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

$F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3$

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be $8.21\times 10^3~N$

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

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3 years ago

Most of the stars in the Milky Way will end their lives as

umka21 [38]

<span> </span>Most of the stars in the Milky Way will end their lives as white dwarfs

4 0

2 years ago

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