Answer:
Step-by-step explanation:
From the given picture,
∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]
m∠ECA = m∠BFD [Given]
m∠ECA + m∠ACB = 180° [Liner pair of angles]
m∠BFD + m∠DFE = 180° [Liner pair of angles]
m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]
m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]
Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]
Answer: its not showing up
Step-by-step explanation:
Answer:
1: AAS, RQC 2: ASA, SRP
Step-by-step explanation:
(1) We are shown that two angles and one side are congruent in the order of AAS. Make sure you write the letters in terms of the corresponding angles. The angles and sides are congruent because the problem labels it for us. For example, B,A,C=R,Q,S. Answers: AAS, RQC.
(2) We are shown that two angles and one side are congruent in the order of ASA. Make sure you write the letters in terms of the corresponding angles again. For example, P,Q,R=P,S,R. The angles are congruent because the problem labels it for us. Side PR is congruent to side PR by reflexive property. Answers: ASA, SRP.
I hope this helped :) Good luck
I believe the answer is 45.
The lcd would be 10x^3y^3
