5b^3 sq rt of a
There's not enough a's
Answer:
1. x = 2
2. x = 5
3. x = 8
4. x = 28
5. x = 13
6. x = 11
7. x = 0
8. x = 72
9. x = 6
10. x = 38
Step-by-step explanation:
hope that helps!
1. subtract 6 on both sides
2. add 3 on both sides
3. divide both sides by 2
4. multiply both sides by 2
5. add 8 on both sides
6. subtract 9 on both sides
7. add 5 on both sides
8. multiply both sides by 6
9. divide both sides by 4
10. add 18 on both sides
Answer:
12x - 6 ≤ - 18
Step-by-step explanation:
We will call "a number" x so
Twelve times a number would be:
12x
Then minus 6
12x - 6
Now we add the less than or equal to sign.
12x - 6 ≤
This is equal to negative eighteen, so:
12x - 6 ≤ - 18
As a bonus we can also solve for x.
12x - 6 = - 18 Add 6 to each side.
12x - 6 + 6 = -18 + 6
12x = -18 + 6
12x = -12 Divide each side by 12
12x/12 = -12/12
x = -12/12
x = -1
So we can say when x ≤ -1 Then 12x - 6 ≤ -18
The answer to your question is: D it has 3
