Answer:
<em>AB = 5√2</em>
<em>AC = √145</em>
<em>BC = √65</em>
Step-by-step explanation:
Using the formula for calculating the distance between two points
D = √(x2-x1)²+(y2-y1)²
For AB A(-3,6),B(2,1),
AB = √(2+3)²+(1-6)²
AB = √(5)²+(-5)²
AB = √25+25
AB = √50
<em>AB = 5√2</em>
For AC A(-3,6) and C(9,5)
AC = √(9+3)²+(5-6)²
AC = √(12)²+(-1)²
AC = √144+1
<em>AC = √145</em>
For BC B(2,1), and C(9,5)
BC = √(9-2)²+(5-1)²
BC = √(7)²+(4)²
BC = √49+16
<em>BC = √65</em>
<em></em>
<em>Since All the sides are difference, hence triangle ABC is a scalene triangle</em>
Hmm, seems to multiply by 5
wait, no
first is multiply by 5
2nd is multiply by 10
3rd is multiply by 15
4th is multiply by 20
seems to be
or
the rule is square the input then multiply by 5
Answer:
x=7
Step-by-step explanation:
The two triangles are similar .
We can use the ratio's of the side to figure out x
2 3.5
-------- = --------------
4 x
Using cross products
2x = 4*3.5
2x=14
Divide each side by 2.
2x/2 = 14/2
x=7
Answer:
A) A graphic rating scale- a scale where the participant places his or her response along a line or continuum; the score or measurement is its distance in millimeters from either endpoint.
B) A multiple rating list- a single interval or ordinal numerical scale where raters respond to a series of objects; results facilitate visualization.I will recommend a multiple rating list, because it is an easier process to conduct in a employee environment.
Step-by-step explanation:
Answer:
<u>GIVEN :-</u>
- ∠A = 15°
- Length of AB (hypotenuse) = 60 ft
<u>TO FIND :-</u>
- Length of BC
- Length of AC
- Area of ΔABC
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
<u>SOLUTION :-</u>
In ΔABC ,
≈ 15.5 ft
≈ 58 ft
Area of ΔABC = 
