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vodomira [7]
3 years ago
9

What is the amount of heat absorbed when the temperature of 75 grams of water increases from 20 to 75

Chemistry
2 answers:
german3 years ago
8 0

Answer:

55°C

Explanation:

original is 20

after gaining heat is 75

75 - 20 = 55

Sindrei [870]3 years ago
7 0

Answer:

17242,5J

Explanation:

Given parameters:

Mass of water  = 75g

Initial temperature  = 20°C

Final temperature  = 75°C

Unknown:

Amount of heat absorbed  = ?

Solution

To find the amount of heat absorbed by water;

      H  = mcΔt

 m is the mass

  c is the specific heat capacity of water  = 4.18J/g°C

 Insert the parameters and solve;

       H  = 75 x 4.18 x (75 - 20)

       H  = 17242,5J

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Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

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Mass of S = 56.1 g

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Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
A ball has 2 kg* m/s of momentum when thrown with a velocity of 8 m/s outwards. Find the mass of the ball.
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Explanation:

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