Answer:
Carnitine Synthesis
Explanation:
Ascorbic acid acts as a cofactor in various hydroxylation and amidation reactions by electron transfer to enzymes that provide reducing equivalents. Accordingly, ascorbic acid is required or facilitates the conversion of certain proline and lysine residues of the procollagen, the oxidation of lysine side chains to proteins, providing hydroxytrimethylsiline for carnitine synthesis. This means that ascorbic acid is essential for the carnitine synthesis.
Carnitine is derived from amino acids and acts as a cofactor for the enzyme acetyltransferase responsible for the transport of fatty acids to mitochondria. Your presence in the body is very important for feeling energetic and strong. The lack of canitine, influenced by the lack of ascorbic acid in individuals suffering from scurvy, causes a lack of energy.
8 moles of H 2O are produced.
First, we need to figure out the chemical equation for producing water with oxygen which is H 2 + O2 = H 2O. Then, we need to balance the equation, resulting in 2H 2 + O2 = 2H 2O.
<h3>How many moles of H2 are required to make one mole of NH3?</h3>
Calculate 0.88074 mol H2's mass. If N2 is too much, 1.776 g H2 is needed to create 10.00 g of NH3. To create 8.2 moles of ammonia, 2 moles of NH3 are created when 1 mole of N2 and 3 moles of H2 mix. 4.1 moles of N2 Fast are consequently needed to make 8.2 moles of NH3.
<h3>
How many moles of h2 are needed to produce a solution?</h3>
An O-H bond has a bond energy of 1 09 Kcal. 3.6. A 38.0mL 0.026M HCl solution and a 0.032M NaOH solution react. Thus, 10 moles of NH 3 are obtained by dividing 15 moles of H2 by the 1.5 moles of H2 required for the product. and 9.3 x 10-3 moles of bromobutane (1.27/137 =.00927moles).
Learn more about H2O:
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Arguably A, B and C are all correct. Atoms of elements can form compounds such as NaCl(table salt). Molecules form molecular compounds and minerals are just complex molecule compounds.
<span>Hydroxide ions as the only negative ions</span>
Answer:
to the right (products side)
Explanation:
The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:
a A + b B → c C + d D
The equilibrium constant expression is:
![K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%5BD%5D%5E%7Bd%7D%20%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%20%7D)
A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).
Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.
Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.
