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Tema [17]
3 years ago
10

Anybody can do this one ?

Mathematics
2 answers:
Viefleur [7K]3 years ago
5 0

Answer:

The first one and the last one are correct

Step-by-step explanation:

Reika [66]3 years ago
4 0

Answer:

hel me I don't now how to start

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How to graph -x + 2y = 6
larisa86 [58]
In order to graph the equation, you need some coordinates, 
So, put x = 0, 
2y = 6. y = 3.  Coordinate = (0, 3)

Now, put y = 0, 
-x = 6
x = -6   Coordinate (-6, 0)

In short, Just mark that two points and draw a line, graph is done

Hope this helps!
3 0
2 years ago
The two legs (labeled x) of the right triangle below have equal length. If the hypotenuse has length 5√2 , solve for x.
leonid [27]

Answer:

x=5

Step-by-step explanation:

Other than using the plain special aspect of a 45-45-90 triangle where the legs are x, x, and x√2, you can solve for this.

Since the two legs have equal length, they are both x. Using the pythagorean theorem:

(x^2)+(x^2)=50 (Because 5 squared is 25 and √2 squared is 2, multiplying them gives you 50).

You can add (x^2) and (x^2) because they are the same terms (x squared).

Simplifying like so gives you:

2x^2=50

Dividing by two on both sides:

x^2=25

Taking the square root of both sides:

x=5

6 0
3 years ago
Please help i never learned this yet lol (Will mark brainliest!!) <br> thx!! :)
galben [10]

Answer:

C

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
The Greenville city soccer league has 1,230 players. Spruceburgh's league has 3 times as many players as the Greenville league.
Nimfa-mama [501]

Answer:

technically you multiply  3690 pick c

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find lim x-&gt;2 for f(x)=
TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0
1 year ago
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