housefly
Explanation:
Because it one of the affective vector of disease carrier and it always roam towards wastes and dirty materials likely to get attracted . And it carries contagious disease from hospitals , infected patients , etc .
Answer:
The rate law is rate = k[NO][O₃]
Option E) is the right answer.
Explanation:
Hi there!
For this generic reaction:
A + B → products
the rate law will be:
rate = k[A]ⁿ[B]ᵃ
this reaction is n-order in A and a-order in B. The overall reaction is the sum of the orders of each reactant, in this case:
Overall order of the reaction = n + a
In our problem, we know that the reaction is first order in O₃ and second order overall. Then:
Overall order of the reaction = Order in NO + Order in O₃
2 = n + 1
2 - 1 = n
n = 1
Then, the reaction is first order in NO and first order in O₃.
The rate law will be:
rate = k[NO][O₃]
The right answer is the option E).
Answer:
100 and 1 atm
Explanation:
I think the gas is given kinetic energy only from its temperature
54.0 ml of a 1.2 m solution was diluted to a total volume of 228 ml
USing dilution equation
M1V1 = M2V2
Where M1V1 is before dilution while M2V2 is after dilution.
Therefore;
M1= 1.20 M, V2= 54 ml,
M2= V2 = 228 ml
1.20 M × 54 ml = M2 × 228 ml
M2 = (1.2 ×54)/ 228 ml
= 0.2842 M
0.2842 × 114 ml = M2 × (114 +111)
M2 = (0.2842 ×114)/ 225
= 0.143995
= 0.144 M
Answer:
Concentration of hydroxide-ion at equivalence point = 
Explanation:
1 mol of 
reacts with 1 mol of KOH to produce 1 mol of 
At equivalence point, all gets converted to .
Moles of produced at equivalence point is equal to moles of KOH added to reach equivalence point.
So, moles of produced = 
Total volume of solution at equivalence point = (25.00+43.76) mL = 68.76 mL
Concentration of at equivalence point = 
produced at equivalence point is due to hydrolysis of . We have to construct an ICE table to calculate concentration of at equivalence point.
I:0.0897 0 0
C: -x +x +x
E: 0.0897-x x x
![\frac{[HC_{3}H_{5}O_{2}][OH^{-}]}{[C_{3}H_{5}O_{2}^{-}]}=K_{b}(C_{3}H_{5}O_{2}^{-})=\frac{10^{-14}}{K_{a}(HC_{3}H_{5}O_{2})}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHC_%7B3%7DH_%7B5%7DO_%7B2%7D%5D%5BOH%5E%7B-%7D%5D%7D%7B%5BC_%7B3%7DH_%7B5%7DO_%7B2%7D%5E%7B-%7D%5D%7D%3DK_%7Bb%7D%28C_%7B3%7DH_%7B5%7DO_%7B2%7D%5E%7B-%7D%29%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7BK_%7Ba%7D%28HC_%7B3%7DH_%7B5%7DO_%7B2%7D%29%7D)
species inside third bracket represent equilibrium concentrations
So, 
or, 
So, 
M =
So, concentration of hydroxide-ion at equivalence point = x M =
