There are four quantum numbers for an orbital, namely, principal quantum number n, azimuthal quantum number l, magnetic quantum number 
and spin quantum number s. No two orbitals can have same value for all the four quantum numbers.
Principal quantum number tells about the position of orbital that is shell number, azimuthal quantum number describes the shape of orbital, for s, p, d, f,... orbitals, the value is 0, 1, 2, 3,... so on. The value of magnetic quantum number varies from -l to +l (including zero), it defines the sub shell of electron. Spin of the electron defines its movement that is clockwise or anticlockwise thus, there are only two possible values for spin quantum number: +1/2 or -1/2.
For 2p orbital, principal quantum number n is 2 (denotes the shell) and azimuthal quantum number for p orbital is 1. Thus, different values for magnetic quantum number will be -l to l that is -1, 0,1.
Therefore, for 2p subshell there are 3 different values.
Answer:
See explanation below
Explanation:
First, you are not providing any data to solve this, so I'm gonna use some that i made up to explain to you, how to solve it. Then, you can go and replace the data you have with the procedure here
The concentration of liquid sodium will be aroun 8.5 MJ of energy, and I will assume that the temperature will not be increased more than 15 °C.
The expression to calculate the amount of energy is:
Q = m * cp * dT
Where:
m: moles needed
cp: specific heat of the substance.
The cp of liquid sodium reported is 30.8 J/ K mole
Replacing all the data in the above formula, and solving for m we have:
m = Q / cp * dT
dT is the increase of temperature. so 15 ° C is the same change for 15 K.
We also need to know that 1 MJ is 1x10^6 J, so replacing all data:
m = 8.5 * 1x10^6 J / 30.8 J/K mole * 15
m = 18,398.27 moles
The molar mass of sodium is 22.95 g/mol so the mass is:
mass = 18,398.27 * 22.95 = 422,240.26 g or simply 422 kg rounded.
Answer:
47,9 kJ/g
Explanation:
The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:
= <em>47,9kJ/g</em>
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I hope it helps!
By putting it in water because all the pease will fall to the bottom
